列出回调? [英] List callbacks?

问题描述

有什么办法可以让list在每次修改list时调用一个函数?

Is there any way to make a list call a function every time the list is modified?

例如:

>>>l = [1, 2, 3]
>>>def callback():
       print "list changed"
>>>apply_callback(l, callback)  # Possible?
>>>l.append(4)
list changed
>>>l[0] = 5
list changed
>>>l.pop(0)
list changed
5

推荐答案

借鉴@sr2222 的建议，这是我的尝试.(我将使用没有语法糖的装饰器):

Borrowing from the suggestion by @sr2222, here's my attempt. (I'll use a decorator without the syntactic sugar):

import sys

_pyversion = sys.version_info[0]

def callback_method(func):
    def notify(self,*args,**kwargs):
        for _,callback in self._callbacks:
            callback()
        return func(self,*args,**kwargs)
    return notify

class NotifyList(list):
    extend = callback_method(list.extend)
    append = callback_method(list.append)
    remove = callback_method(list.remove)
    pop = callback_method(list.pop)
    __delitem__ = callback_method(list.__delitem__)
    __setitem__ = callback_method(list.__setitem__)
    __iadd__ = callback_method(list.__iadd__)
    __imul__ = callback_method(list.__imul__)

    #Take care to return a new NotifyList if we slice it.
    if _pyversion < 3:
        __setslice__ = callback_method(list.__setslice__)
        __delslice__ = callback_method(list.__delslice__)
        def __getslice__(self,*args):
            return self.__class__(list.__getslice__(self,*args))

    def __getitem__(self,item):
        if isinstance(item,slice):
            return self.__class__(list.__getitem__(self,item))
        else:
            return list.__getitem__(self,item)

    def __init__(self,*args):
        list.__init__(self,*args)
        self._callbacks = []
        self._callback_cntr = 0

    def register_callback(self,cb):
        self._callbacks.append((self._callback_cntr,cb))
        self._callback_cntr += 1
        return self._callback_cntr - 1

    def unregister_callback(self,cbid):
        for idx,(i,cb) in enumerate(self._callbacks):
            if i == cbid:
                self._callbacks.pop(idx)
                return cb
        else:
            return None


if __name__ == '__main__':
    A = NotifyList(range(10))
    def cb():
        print ("Modify!")

    #register a callback
    cbid = A.register_callback(cb)

    A.append('Foo')
    A += [1,2,3]
    A *= 3
    A[1:2] = [5]
    del A[1:2]

    #Add another callback.  They'll be called in order (oldest first)
    def cb2():
        print ("Modify2")
    A.register_callback(cb2)
    print ("-"*80)
    A[5] = 'baz'
    print ("-"*80)

    #unregister the first callback
    A.unregister_callback(cbid)

    A[5] = 'qux'
    print ("-"*80)

    print (A)
    print (type(A[1:3]))
    print (type(A[1:3:2]))
    print (type(A[5]))

这样做的好处在于，如果您发现忘记考虑某个特定方法，只需添加 1 行代码即可.(例如，我直到现在才忘记 __iadd__ 和 __imul__ :)

The great thing about this is if you realize you forgot to consider a particular method, it's just 1 line of code to add it. (For example, I forgot __iadd__ and __imul__ until just now :)

编辑

我稍微更新了代码以兼容 py2k 和 py3k.此外，切片会创建一个与父对象类型相同的新对象.请随意继续在这个食谱中戳洞，这样我就可以做得更好.这实际上看起来是一个非常整洁的东西......

I've updated the code slightly to be py2k and py3k compatible. Additionally, slicing creates a new object of the same type as the parent. Please feel free to continue poking holes in this recipe so I can make it better. This actually seems like a pretty neat thing to have on hand ...

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