如何将复杂的 MySQL 查询转换为 Doctrine2 [英] How to convert a complex MySQL Query to Doctrine2

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本文介绍了如何将复杂的 MySQL 查询转换为 Doctrine2的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试使用学说创建加权搜索.这就是我在直接 sql 中的做法.我想知道如何将它转换为我们的学说 2 方法.我正在尝试使用 symfony2 进行此搜索.

I am trying to create a weighted search using doctrine. This is how i do it in straight sql. Im wondering how i would convert it to us the doctrine2 methods. I am trying to do this search using symfony2.

此外,如果有更好的方法可以做到这一点,我对此持开放态度.谢谢.

Also if there is a better way to do this I am open to that to. Thanks.

"SELECT   *,
    IF(`name` LIKE "%$searchterm%",  20,
    IF(`name` LIKE "%$searchterm%", 10, 0)) +
    IF(`address` LIKE "%$searchterm%", 5,  0) +
    IF(`city`   LIKE "%$searchterm%", 1,  0)
    AS `weight`
 FROM `table_name`
 WHERE
     (`name` LIKE "%$searchterm%" OR
      `address` LIKE "%$searchterm%" OR
      `city`  LIKE "%$searchterm%")
 ORDER BY `weight` DESC
 LIMIT 20"

推荐答案

是的,可以使用 DQL 来完成.Doctrine 不支持 IF 语句.但是同样的功能可以通过 CASE 语句来实现.示例 DQL 如下所示,

Yes, it can be done using DQL. Doctrine does not support IF statement. But same functionality can be achieved by CASE statement. Sample DQL is given bellow,

$dql = "SELECT t, 
          (CASE 
            WHEN (t.name LIKE :searchterm) THEN 10 
            ELSE 0
          END) + 
          (CASE 
            WHEN (t.address LIKE :searchterm) THEN 5 
            ELSE 0
          END) + 
          (CASE 
            WHEN (t.city LIKE :searchterm) THEN 1 
            ELSE 0
          END)
          AS weight 
        FROM YourBundleName:TableName t 
        WHERE 
          t.name LIKE :searchterm OR 
          t.address LIKE :searchterm OR 
          t.city LIKE :searchterm
        ORDER BY weight DESC
      ";
$query = $entityManager->createQuery($dql)
  ->setFirstResult(0)
  ->setMaxResults(20)
  ->setParameter('searchterm' , $searchterm)
  ;

这篇关于如何将复杂的 MySQL 查询转换为 Doctrine2的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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