GraphQL 我将如何编写查询以按名字查找 [英] GraphQL How would I write a query to find by first name

问题描述

我正在尝试了解 Graph QL 并有一个基本的示例工作.例如如果我传入此查询，我将返回与 id 的匹配项.

I am trying to understand Graph QL and have a basic example working. e.g. if I pass in this query I get back the match with the id.

query {
  person(id:"4090D8F6-EFC4-42CD-B55C-E2203537380C")
  {
    firstname
    surname
  }
}

我的数据只是一组静态的测试数据，我现在想要做的是返回名字与我提供的内容相匹配的所有用户.我很困惑如何写这个，因为 id null 检查似乎阻止了我！?

My data is just a static set of test data, what I would like to do now is return all users that have a first name matching what I provide. I am baffled how I would write this as the id null check seems to stop me!?

我的 PersonQuery 如下所示:

My PersonQuery Looks like this:

public class PersonQuery : ObjectGraphType<Person>
{

    public PersonQuery(ShoppingData data)
    {
        Field<PersonType>(
            "person",
            description: "A Person",
            arguments: new QueryArguments(
                new QueryArgument<NonNullGraphType<IdGraphType>>
                {
                    Name = "id",
                    Description = "The id of the person"
                }),
            resolve: ctx =>
            {
                return data.GetById(ctx.GetArgument<Guid>("id"));
            });

    }
}

我将如何做到这一点，以便我可以按名字返回人员列表，不知道这是否是下面的有效查询，但想要一些有关如何执行此操作以及工作 ID 的帮助示例.

How would I make it so that I can return a list of persons by the first name, don't event know if this is a valid query below but would like some help on how I could do this along with the working id example.

query {
  person
  {
    firstname: ("Andrew")
    surname
  }
}

答案更新 - DavidG 提供

我按照上面提到的做了，所以我的 PersonQuery 现在看起来像这样

I did as was mentioned so my PersonQuery now looks like this

public class PersonQuery : ObjectGraphType<Person>
    {

        public PersonQuery(ShoppingData data)
        {
            Field<PersonType>(
                name: "person",
                description: "A Person",
                arguments: new QueryArguments(
                    new QueryArgument<IdGraphType>
                    {
                        Name = "id",
                        Description = "The id of the person"
                    }),
                resolve: ctx =>
                {
                     return data.GetById(ctx.GetArgument<Guid>("id"));
                });

            Field<ListGraphType<PersonType>>(
                name : "persons",
                description: "Persons",
                arguments: new QueryArguments(
                    new QueryArgument<StringGraphType>
                    {
                        Name = "firstname",
                        Description = "The firstname of the person"
                    },
                    new QueryArgument<StringGraphType>
                    {
                        Name = "surname",
                        Description = "The surname of the person"
                    }),
                resolve: ctx =>
                {
                    var firstName = ctx.GetArgument<String>("firstname");
                    var surname = ctx.GetArgument<String>("surname");
                    return data.Filter(firstName, surname);
                });

        }
    }

然后我可以按如下方式运行 graphql 查询:

I could then run the graphql query as follows:

query {
  persons(firstname: "Andrew", surname: "P")
  {
    firstname
    surname
  }
}

推荐答案

您需要更改此处的字段以使 id 参数可选或创建一个新字段(可能称为 persons 或 people) 并添加您解析到数据存储库中的新参数.就我个人而言，我更喜欢做后者并创造一个新领域.例如:

You would need to either change the field you have here to make the id parameter optional or create a new field (maybe called persons or people) and add a new parameter that you parse into your data repository. Personally, I would favour doing the latter and create a new field. For example:

public PersonQuery(ShoppingData data)
{
    Field<PersonType>( /* snip */ );

    //Note this is now returning a list of persons
    Field<ListGraphType<PersonType>>(
        "people", //The new field name
        description: "A list of people",
        arguments: new QueryArguments(
            new QueryArgument<NonNullGraphType<StringGraphType>>
            {
                Name = "firstName", //The parameter to filter on first name
                Description = "The first name of the person"
            }),
        resolve: ctx =>
        {
            //You will need to write this new method
            return data.GetByFirstName(ctx.GetArgument<string>("firstName"));
        });
}

现在您只需要自己编写 GetByFirstName 方法.查询现在看起来像这样:

And now you just need to write the GetByFirstName method yourself. The query would now look like this:

query {
  people(firstName:"Andrew")
  {
    firstname
    surname
  }
}

现在您可能会发现 GetByFirstName 是不够的，您还需要一个姓氏参数，并且它们是可选的，因此您可以执行以下操作:

Now you may find that GetByFirstName isn't enough and you also want a surname parameter too, and for them to be optional, so you could do something like this:

Field<ListGraphType<PersonType>>(
    "people",
    description: "A list of people",
    arguments: new QueryArguments(
        new QueryArgument<StringGraphType>
        {
            Name = "firstName", //The parameter to filter on first name
            Description = "The first name of the person"
        },
        new QueryArgument<StringGraphType>
        {
            Name = "surname",
            Description = "The surname of the person"
        }),
    resolve: ctx =>
    {
        //You will need to write this new method
        return data.SearchPeople(
            ctx.GetArgument<string>("firstName"), 
            ctx.GetArgument<string>("surame"));
    });

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