如何使用 jQuery 对 JSON 数据进行分页? [英] How to use jQuery to paginate JSON data?

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问题描述

重复:

很好的 jquery 分页插件与 json 数据一起使用...

我的 JSON 数据是这样的

My JSON data looks like this

{
    "Table": [{
        "Emp_Id": "3",
        "Identity_No": "",
        "Emp_Name": "Jerome",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Supervisior",
        "Desig_Description": "Supervisior of the Construction",
        "SalaryBasis": "Monthly",
        "FixedSalary": "25000.00"
    }, {
        "Emp_Id": "4",
        "Identity_No": "",
        "Emp_Name": "Mohan",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Acc ",
        "Desig_Description": "Accountant",
        "SalaryBasis": "Monthly",
        "FixedSalary": "200.00"
    }, {
        "Emp_Id": "5",
        "Identity_No": "",
        "Emp_Name": "Murugan",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason",
        "Desig_Description": "Mason",
        "SalaryBasis": "Weekly",
        "FixedSalary": "150.00"
    }, {
        "Emp_Id": "6",
        "Identity_No": "",
        "Emp_Name": "Ram",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason",
        "Desig_Description": "Mason",
        "SalaryBasis": "Weekly",
        "FixedSalary": "120.00"
    }, {
        "Emp_Id": "7",
        "Identity_No": "",
        "Emp_Name": "Raja",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason",
        "Desig_Description": "Mason",
        "SalaryBasis": "Weekly",
        "FixedSalary": "135.00"
    }, {
        "Emp_Id": "8",
        "Identity_No": "",
        "Emp_Name": "Raja kumar",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason Helper",
        "Desig_Description": "Mason Helper",
        "SalaryBasis": "Weekly",
        "FixedSalary": "105.00"
    }, {
        "Emp_Id": "9",
        "Identity_No": "",
        "Emp_Name": "Lakshmi",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Mason Helper",
        "Desig_Description": "Mason Helper",
        "SalaryBasis": "Weekly",
        "FixedSalary": "100.00"
    }, {
        "Emp_Id": "10",
        "Identity_No": "",
        "Emp_Name": "Palani",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Carpenter",
        "Desig_Description": "Carpenter",
        "SalaryBasis": "Weekly",
        "FixedSalary": "200.00"
    }, {
        "Emp_Id": "11",
        "Identity_No": "",
        "Emp_Name": "Annamalai",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Carpenter",
        "Desig_Description": "Carpenter",
        "SalaryBasis": "Weekly",
        "FixedSalary": "220.00"
    }, {
        "Emp_Id": "12",
        "Identity_No": "",
        "Emp_Name": "David",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Steel Fixer",
        "Desig_Description": "Steel Fixer",
        "SalaryBasis": "Weekly",
        "FixedSalary": "220.00"
    }, {
        "Emp_Id": "13",
        "Identity_No": "",
        "Emp_Name": "Chandru",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Steel Fixer",
        "Desig_Description": "Steel Fixer",
        "SalaryBasis": "Weekly",
        "FixedSalary": "220.00"
    }, {
        "Emp_Id": "14",
        "Identity_No": "",
        "Emp_Name": "Mani",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Steel Helper",
        "Desig_Description": "Steel Helper",
        "SalaryBasis": "Weekly",
        "FixedSalary": "175.00"
    }, {
        "Emp_Id": "15",
        "Identity_No": "",
        "Emp_Name": "Karthik",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Wood Fixer",
        "Desig_Description": "Wood Fixer",
        "SalaryBasis": "Weekly",
        "FixedSalary": "195.00"
    }, {
        "Emp_Id": "16",
        "Identity_No": "",
        "Emp_Name": "Bala",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Wood Fixer",
        "Desig_Description": "Wood Fixer",
        "SalaryBasis": "Weekly",
        "FixedSalary": "185.00"
    }, {
        "Emp_Id": "17",
        "Identity_No": "",
        "Emp_Name": "Tamil arasi",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Wood Helper",
        "Desig_Description": "Wood Helper",
        "SalaryBasis": "Weekly",
        "FixedSalary": "185.00"
    }, {
        "Emp_Id": "18",
        "Identity_No": "",
        "Emp_Name": "Perumal",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Cook",
        "Desig_Description": "Cook",
        "SalaryBasis": "Weekly",
        "FixedSalary": "105.00"
    }, {
        "Emp_Id": "19",
        "Identity_No": "",
        "Emp_Name": "Andiappan",
        "Address": "Madurai",
        "Date_Of_Birth": "",
        "Desig_Name": "Watchman",
        "Desig_Description": "Watchman",
        "SalaryBasis": "Weekly",
        "FixedSalary": "150.00"
    }]
}

此 JSON 数据中有 22 条记录.如何使用 jQuery 将此 JSON 数据分页为每页 5 个?

There are 22 records in this JSON data. How to paginate this JSON data to 5 per page using jQuery?

替代文字 http://img218.imageshack.us/img218/7757/fivej.jpg

上图是我使用 jQuery 迭代的员工列表的摘要视图.

The above image is my summary view of employee list iterated using jQuery.

var jsonObj = JSON.parse(HfJsonValue);
    for (var i = jsonObj.Table.length - 1; i >= 0; i--) {
        var employee = jsonObj.Table[i];
        $('<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>').insertAfter('#ResultsDiv');
    }

我有 22 条记录.现在它可能会增长.如何使用 jQuery 分页对 JSON 数据进行分页?

I get 22 records. Now it may grow. How to paginate the JSON data by using jQuery pagination?

推荐答案

您可以使用 Array.splice-method 从数组中创建所需大小的组:

You can use the Array.splice-method to create groups of the size you want from the array:

// Parse json etc.
var json = [...];
// Fetch the data for a page from the json-result object
var page = 1,
    recPerPage = 5,
    // Use Math.max to ensure that we at least start from record 0
    startRec = Math.max(page - 1, 0) * 5,
    // The end index of Array.splice doesn't have to be within boundaries,
    // But if you want to ensure that it does, then use 
    // Math.min(startRec + recPerPage, json.table.length)
    endRec = startRec + recPerPage
    recordsToShow = json.table.splice(startRec, endRec);

recordsToShow 现在包含要为页面显示的记录数组.重构出 page = 1 并将其作为参数,对 recPerPage = 5 执行相同的操作,您应该很高兴.您可以使用 jQuery.each 遍历 recordsToShow,并使用某种模板系统从每条记录创建 HTML 元素.

recordsToShow now contains an array of records to show for a page. Refactor out page = 1 and take it as a parameter, and do the same for recPerPage = 5, and you should be good to go. You can use jQuery.each to iterate through recordsToShow, and use some kind of templating system to create HTML-elements from each record.

您还应该对 startRec 添加某种检查以确保起始记录在边界内.如果不是,则显示第 1 页,或向用户显示错误消息.

You should also add some kind of check to startRec to ensure that the starting record is within boundaries. If it is not, then either display page 1, or display an error message to the user.

这篇关于如何使用 jQuery 对 JSON 数据进行分页?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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