Scrapy:谷歌抓取不起作用 [英] Scrapy: Google Crawl doesn't work

问题描述

当我尝试在 Google 上抓取搜索结果时，Scrapy 只会生成 Google 主页:http://pastebin.com/FUbvbhN4

When I try to crawl Google for search results, Scrapy just yields the Google home page: http://pastebin.com/FUbvbhN4

这是我的蜘蛛:

import scrapy

class GoogleFinanceSpider(scrapy.Spider):
    name = "google"
    start_urls = ['http://www.google.com/#q=finance.google.com:+3m+co']
    allowed_domains = ['www.google.com']

    def parse(self, response):
        filename = response.url.split("/")[-2] + '.html'
        with open(filename, 'wb') as f:
            f.write(response.body)

这个网址作为起始网址有什么问题吗?当我在浏览器中打开它时——通过将它放在地址栏中(而不是通过填写搜索表单)——我得到了有效的搜索结果.

Is there something wrong with this url as a starting url? When I open it in my browser -- by putting it in the address bar (not by filling in the search form) -- I get valid search results.

推荐答案

是的，看起来那个地址正在重定向到主页:

Yes, looks like that address is redirecting to the home page:

带有 scrapy shell 的示例 http://www.google.com/#q=finance.google.com:+3m+co:

...
[s]   request    <GET http://www.google.com/#q=finance.google.com:+3m+co>
[s]   response   <200 http://www.google.com/>
...

检查您的 url 是有道理的，它不包含参数，但是 #q(不是 url 参数)和浏览器是识别这一点并使其成为谷歌搜索的浏览器，所以它不完全是一个 url 路径.

Checking your url it makes sense, it isn't containing parameters, but #q (which isn't a url parameter) and the browser is the one recognizing that and making it a google search, so it is not exactly a url path.

正确的谷歌搜索网址是:http://www.google.com/search?q=YOURQUERY

the correct google search url is: http://www.google.com/search?q=YOURQUERY

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