如何在linux内核空间中获取当前小时(一天中的时间) [英] How to get current hour (time of day) in linux kernel space

问题描述

我正在编写一个内核模块来检查时间是否在两个指定的小时之间，如果是则禁用输入.这与我想确保我早点睡觉有关.(我知道我也可以使用多种不同的技术，包括 cron 等，但我想学习内核编程......)

I'm writing a kernel module that checks to see if the time is between two specified hours, and disables input if it is. This has to do with me wanting to make sure I go to bed early. (I know I could also use any number of different techniques including cron etc, but I wanted to learn kernel programming...)

作为第一个版本，我因此检查当前小时是否在开始和结束之间，这是通过模块的参数设置的.

As a first version, I therefore check if the current hour is between start and end, which are set via parameters to the module.

因此，我的问题是:如何获取当前小时数?我无法访问标准库中的常用时间函数，因为我在内核空间中.我猜我应该为此使用 do_gettimeofday() ，但这只会给我几秒和几纳秒，而我在当天需要几个小时.

My question is therefore : How do I get the current hour? I have no access to the usual time functions in the standard library because I am in kernel space. I'm guessing that I should be using do_gettimeofday() for this, but that only gives me seconds and nanoseconds, and I need hours in the current day.

谢谢.

推荐答案

time_to_tm 函数可以为您提供帮助，它返回结构 tm.时区在变量 sys_tz 中可用，它可以帮助您设置正确偏移以获得当地时间.

time_to_tm function can be of your help, which returns the structure tm. Timezone available in variable sys_tz, it can help you to set your offset properly to get local time.

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