对象引用的变量重新分配使其他对象保持不变(无“传递"分配) [英] Variable re-assignment of object reference leaves other object unaltered (no “transitive” assignment)

问题描述

我有一个要替换的对象.

I have an object that I want to replace.

var obj1 = { x: "a" };
var ref = obj1;
var obj2 = { y: "b" };

obj1 = obj2;

这导致 ref 等效于 { x: "a" }，但我希望它也被更改为指向 obj2 得到 ref 等价于 { y: "b" }.

This results in ref being equivalent to { x: "a" }, but I want it to get changed as well to point to obj2 to get ref being equivalent to { y: "b" }.

推荐答案

不可能.JS 通过引用的副本传递对象，因此在步骤 var ref = obj1 中，您实际上并没有像在像 C 这样的语言中那样分配引用指针.相反，您正在创建一个副本指向一个类似于 {x: 'a'} 的对象的引用.

Not possible. JS passes objects by a copy of the reference, so in the step var ref = obj1 you're not actually assigning a reference pointer like you would in a language like C. Instead you're creating a copy of a reference that points to an object that looks like {x: 'a'}.

有关您拥有的其他选项，请参阅此答案:https://stackoverflow.com/a/17382443/6415214.

See this answer for other options you have: https://stackoverflow.com/a/17382443/6415214.

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