如何在 Java 中使用等效于 C++ 的引用参数? [英] How do I use an equivalent to C++ reference parameters in Java?
问题描述
假设我在 C++ 中有这个:
Suppose I have this in C++:
void test(int &i, int &j)
{
++i;
++j;
}
这些值在函数内部被改变,然后在外部使用.我怎么能写出在 Java 中做同样事情的代码?我想我可以返回一个封装了这两个值的类,但这看起来真的很麻烦.
The values are altered inside the function and then used outside. How could I write a code that does the same in Java? I imagine I could return a class that encapsulates both values, but that seems really cumbersome.
推荐答案
使用包装器模拟引用.
可以以某种方式模拟这种行为的一种方法是创建一个通用包装器.
Simulating reference with wrappers.
One way you can have this behavior somehow simulated is create a generic wrapper.
public class _<E> {
E ref;
public _( E e ){
ref = e;
}
public E g() { return ref; }
public void s( E e ){ this.ref = e; }
public String toString() {
return ref.toString();
}
}
我不太相信这段代码的价值,因为我无法帮助它,我不得不编写代码 :)
I'm not too convinced about the value of this code, by I couldn't help it, I had to code it :)
原来是这样.
示例用法:
public class Test {
public static void main ( String [] args ) {
_<Integer> iByRef = new _<Integer>( 1 );
addOne( iByRef );
System.out.println( iByRef ); // prints 2
_<String> sByRef = new _<String>( "Hola" );
reverse( sByRef );
System.out.println( sByRef ); // prints aloH
}
// Change the value of ref by adding 1
public static void addOne( _<Integer> ref ) {
int i = ref.g();
ref.s( ++i );
// or
//int i = ref.g();
//ref.s( i + 1 );
}
// Reverse the vale of a string.
public static void reverse( _<String> otherRef ) {
String v = otherRef.g();
String reversed = new StringBuilder( v ).reverse().toString();
otherRef.s( reversed );
}
}
这里有趣的是,通用包装类名称是_",它是一个有效的类标识符.所以声明如下:
The amusing thing here, is the generic wrapper class name is "_" which is a valid class identifier. So a declaration reads:
对于整数:
_<Integer> iByRef = new _<Integer>( 1 );
对于字符串:
_<String> sByRef = new _<String>( "Hola" );
对于任何其他类
_<Employee> employee = new _<Employee>( Employee.byId(123) );
方法s"和g"代表设置和获取:P
The methods "s" and "g" stands for set and get :P
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