多行卷曲命令 [英] Multiline curl command
本文介绍了多行卷曲命令的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试修改使用 Google Chrome Dev Tools 捕获的 curl 请求.
I am trying to modify a curl request that was captured with Google Chrome Dev Tools.
命令如下
curl "http://WEBSITE" -H "Host: WEBSITE" -H "Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8" -H "Accept-Language: en-US,en;q=0.5" --compressed -H "Content-Type: multipart/form-data; boundary=---------------------------1184875127259" --data-binary "-----------------------------1184875127259"^
"Content-Disposition: form-data; name=""FORM1"""^
"FORM1DATA"^
"-----------------------------1184875127259"^
"Content-Disposition: form-data; name=""FORM2"""^
"FORM2DATA"^
"-----------------------------1184875127259"^
"Content-Disposition: form-data; name=""FORM3"""^
"FORM3DATA"^
"-----------------------------1184875127259"^
"Content-Disposition: form-data; name=""embed"""^
"true"^
"---------------------------1184875127259--"^
""
Form#
是表单的名称,Form#Data
是我在表单中提交的数据.
Form#
is the name of the form and Form#Data
is the data I submitted in the forms.
如何使它成为一个单行 curl 请求,我可以将其复制到我的命令行中并让它做与我的浏览器所做的相同的事情?
How would I make this be a single line curl request I can just copy into my command line and have it do the same thing that my browser did?
推荐答案
对于 Linux 和 MacOS: 使用 转义字符:
curl "http://WEBSITE" -H "Host: WEBSITE"
-H "Accept: text/html,application/xhtml+xml
,application/xml;q=0.9,*/*;q=0.8"
对于 Windows: 使用 ^
转义字符:
curl "http://WEBSITE" -H "Host: WEBSITE" ^
-H "Accept: text/html,application/xhtml+xml ^
,application/xml;q=0.9,*/*;q=0.8"
这篇关于多行卷曲命令的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文