Symfony2 - 一种获取捆绑包中所有控制器的方法? [英] Symfony2 - A way to get all controllers of a bundle?

问题描述

有没有办法获得一个包的所有控制器(和类)?包括所有父控制器?

Is there a way to get all controllers (and the class) of a bundle ? Including all parent contollers ?

谢谢

推荐答案

最现实的方法是获取路由的端点.

The most realistic way to this is is by getting the endpoints of the routes.

控制器没有文档所暗示的必需结构.动作方法不需要在名称中加上 Action 后缀.以这种方式记录的原因是因为很多人在他们的路由 yml 中使用 catch all 配置，需要后缀来猜测端点.

A controller doesn't have a required structure as the documentation implies. An action method does not need to be suffixed with Action in the name. The reason it is documented this way is because a lot of people use the catch all configuration in their routing yml, the suffix is needed to guess the endpoints.

当你打印出路线时:

print_r($this->container->get('router')->getRouteCollection()->all());

您将看到针对每个路由使用的控制器方法.这些路由在技术上不属于"任何包，因为您可以将路由指向任何类的任何方法.

You will see the controller methods used against each route. These routes technically don't 'belong' to any bundle since you can point a route at any method of any class.

但是，您可以使用列表和一些字符串魔法来告诉基于命名空间的包.

However, you can use the list and a bit of string magic to tell the bundle based on the namespace.

请记住，像 web_profiler.controller.profiler:infoAction 这样的 _controller 意味着该方法属于通过依赖注入实例化的服务.

Bare in mind that a _controller like web_profiler.controller.profiler:infoAction means the method belongs to a service instantiated via dependency injection.

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