Android 中的倒置 ListView? [英] Inverted ListView in Android?

问题描述

有没有一种简单的方法可以以相反的顺序显示 ListView?我正在尝试创建一个基于对话的应用程序，并希望最近的条目位于 ListView 的底部.我知道transcriptMode 和stackFromBottom，但是我的问题是数据的顺序.

Is there an easy way to display a ListView in reverse order? I am trying to create a conversation-based app, and would like the most recent entries to be at the bottom of the ListView. I am aware of transcriptMode and stackFromBottom, however my problem is the order of the data.

假设我有 100 个对话项目，并且想要显示 80-100 个项目，其中 100 是最近的对话项目.我想显示 80-100，这意味着在我的查询中使用 ORDER BY id desc LIMIT 20，这会强制将项目按 100 到 80 排序，这与我需要的相反.我目前有一些讨厌的内部查询代码，但我觉得应该有一个更简单的解决方案，即反转光标或简单地反转 ListView.

Say I have 100 conversation items, and want to display items 80-100, with 100 being the most recent conversation item. I would like to show 80-100, which implies an ORDER BY id desc LIMIT 20 in my query, which forces the items to be sorted 100 to 80, the opposite of what I need. I currently have some nasty inner query code, but feel like there should be a simpler solution based on reversing the cursor or simply inverting the ListView.

推荐答案

在baseAdapter内部，用于getView() 方法，而不是获取索引位置"中数据中的项目，而是使用相反的方法，意思是:numberOfItems 减去位置.

inside the baseAdapter, for the getView() method , instead of getting the item in the data in index "position" , use the opposite , meaning : numberOfItems minus the position .

至于显示项目数，这也在 baseAdapter 中:将 getCount() 返回的值设置为您希望的值(在您的示例中为 20，尽管 80-100 意味着它应该是 21 ) .

as for showing the number of items , that's also inside the baseAdapter : set the value returned by getCount() to be the one you wish it to be (20 in your example,though 80-100 implies that it should be 21 ) .

顺便说一句，在 listView 的情况下，您似乎是初学者.我可以建议观看这个视频吗:http://www.youtube.com/watch?v=wDBM6wVEO70

btw, it seems you are a starter in the case of listView . may i suggest watching this video: http://www.youtube.com/watch?v=wDBM6wVEO70

还要检查 sdk manager 提供的 api-demos.他们有很多例子.

also check the api-demos provided by the sdk manager . they have plenty of examples there.

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