直接打印到文本视频内存时出现意外输出 [英] Unexpected output when printing directly to text video memory
问题描述
我正在用 C 开发内核,并创建了一些可以在视频内存的屏幕上打印的内容.我希望视频内存中的第一个字节是要打印的字符,第二个字节告诉颜色.但我的程序有一些不同的东西,但它有效!!这是非常出乎意料和不寻常的.
I am developing a kernel in C and created something to print on screen on video memory. I expected that the first byte in video memory would be the character to print and the second byte tells the color. But my program has something different but it works!! It is very unexpected and unusual.
我的内核代码-
#define VIDEO_MEM 0xb8000
void write_string( int colour, const unsigned char *string );
void main()
{
unsigned char *vid = (unsigned char*) VIDEO_MEM;
int i=0;
for (i = 0; i < 2000; i++)
{
*vid = ' ';
*(vid+2) = 0x1f;
vid += 2;
}
write_string(0x1f,"The Kernel has been loaded successfully!!");
}
void write_string( int colour, const unsigned char *string ) {
unsigned char *vid = (unsigned char*) VIDEO_MEM;
while(*string != 0)
{
*(vid) = *string;
*(vid+2) = colour;
++string;
vid+=2;
}
}
它在 *vid
上打印字符,在 *(vid+2)
上打印颜色,然后将 vid
增加 2.它然后应该替换并打印 *(vid+2)
上的下一个字符.所以,颜色应该会消失,但它仍然有效.
It prints the character on *vid
and the color on *(vid+2)
and then increments the vid
by 2. It should then replace and print the next char on *(vid+2)
. So, the color should go but it still works.
另外,颜色应该在*(vid+1)
当我使用 *(vid+1)
而不是 *(vid+2)
打印字符串时,屏幕显示向下箭头字符(带有 ACII 代码 0x1f
我想成为颜色)替换整个字符串.
When I use *(vid+1)
instead of *(vid+2)
to print the string, the screen shows down arrow characters (with ACII code 0x1f
which I wanted to be the color) replacing the entire string.
为什么代码表现得如此异常??
Why does the code behave so unusual??
有人可以帮忙吗?
编辑
我已经编辑了我的代码,现在它会打印字符串.但另一个问题出现了.我添加了对在特定行号上打印的支持.但是现在这会将字符串向后移动一个字符.
I have edited my code and now it prints string. But another problem arose. I added a support for printing on particular line number. But now this shifts the string backwards by one character.
void write_string( int colour, const unsigned char *string, int pos ) {
unsigned char *vid = (unsigned char*) VIDEO_MEM;
vid+=pos*160;
while(*string != 0)
{
*vid = colour;
*(vid+1) = *string;
++string;
vid+=2;
}
}
所以,如果我告诉它在第 10 行打印,它会在第 9 行的最后一个字符上打印第一个字符,然后继续.
So, If I tell it to print on line 10, it prints the first character on the last character of the 9th line and then continues.
我还有一个字符打印功能,它只打印花括号 (}
) 而不是给定的字符,并且在给定位置的后面也有一个字符(如 write_string 中的错误)
函数).它也不会改变作为参数给出的字符背景颜色.
I also have a character printing function that justs prints curly braces (}
) instead of the given character and that too one character backwards of the given position (like the error in the write_string
function). Also it doen't change the character background color given as argument.
void putChar(char character, short col, short row, char attr) {
unsigned char* vid_mem = (unsigned char *) VIDEO_MEM;
int offset = (row*80 + col)*2;
vid_mem += offset;
if(!attr) {
attr = 0x0f;
}
*vid_mem = (attr<<8)+character;
}
<小时>
编辑 2
我的引导加载程序:
[org 0x7c00]
KERNEL equ 0x1000
mov [BOOT_DRIVE],dl
mov bp,0x9000
mov sp,bp
mov bx, msgReal
call print_string
call load_kernel
call switch_to_pm
jmp $
%include 'boot/bios.ASM'
%include 'boot/gdt.ASM'
%include 'boot/protected_mode.ASM'
%include 'boot/print32.ASM'
[bits 16]
load_kernel:
mov bx,msgKernel
call print_string
mov bx, KERNEL
mov dh, 15
mov dl, [BOOT_DRIVE]
call disk_load
ret
[bits 32]
BEGIN_PM:
mov ebx, msgProt
call print_string32
call KERNEL
jmp $
BOOT_DRIVE db 0
msgReal db "Booted in 16-bit mode",0
msgProt db "Successfully switched to 32-bit mode",0
msgKernel db "Loading the kernel onto memory",0
times 510-($-$$) db 0
dw 0xaa55
bios.ASM -
;BIOS Functions
[bits 16]
print_string:
pusha
mov cx,bx
mov ah,0x0e
printStringStart:
mov al,[bx]
cmp al,0
je done
int 0x10
inc bx
jmp printStringStart
done:
popa
ret
print_word:
pusha
mov ax,0x0000
mov cl,0x10
mov al,bh
div cl
call printDig
mov al,bh
and al,0x0f
call printDig
mov ax,0x0000
mov al,bl
div cl
call printDig
mov al,bl
and al,0x0f
call printDig
popa
ret
printDig:
cmp al,0x9
jg alpha
add al,'0'
mov ah,0x0e
int 0x10
jmp pDigDone
alpha:
sub al,0xa
add al,'A'
mov ah,0x0e
int 0x10
pDigDone:
ret
hex_prefix: db '0x',0
disk_load:
push dx
mov ah,0x02
mov al,dh
mov ch,0x00
mov dh,0x00
mov cl,0x02
int 0x13
jc disk_error
pop dx
cmp dh,al
jne disk_error
ret
disk_error:
mov ah,0x0e
mov al,'X'
int 0x10
mov bx,errMsg
call print_string
jmp $
errMsg:
db "Disk Read Error....."
times 80-20 db " "
db 0
gdt.ASM -
gdt_start:
gdt_null:
dd 0x0
dd 0x0
gdt_code:
dw 0xffff
dw 0x0
db 0x0
db 10011010b
db 11001111b
db 0x0
gdt_data:
dw 0xffff
dw 0x0
db 0x0
db 10010010b
db 11001111b
db 0x0
gdt_end:
gdt_descriptor:
dw gdt_end - gdt_start - 1
dd gdt_start
CODE_SEG equ gdt_code - gdt_start
DATA_SEG equ gdt_data - gdt_start
protected_mode.ASM -
protected_mode.ASM -
[bits 16]
switch_to_pm:
cli
lgdt [gdt_descriptor]
mov eax, cr0
or eax, 0x1
mov cr0, eax
jmp CODE_SEG:init_pm
[bits 32]
init_pm:
mov ax, DATA_SEG
mov ds, ax
mov ss, ax
mov es, ax
mov fs, ax
mov gs, ax
mov ebp,0x90000
mov esp,0x90000
call BEGIN_PM
print32.ASM -
print32.ASM -
[bits 32]
VIDEO_MEM equ 0xb8000
DEF_COLOR equ 0x0f
print_string32:
pusha
mov edx,VIDEO_MEM
print_string32_loop:
mov al, [ebx]
mov ah, DEF_COLOR
cmp al,0
je print_string32_end
mov [edx],ax
inc ebx
add edx,2
jmp print_string32_loop
print_string32_end:
popa
ret
在链接调用主函数时,我还在内核之前添加了一个 kernel_start.asm 文件 -
I also add a kernel_start.asm file just before the kernel while linking to call the main function -
[bits 32]
[extern main]
call main
jmp $
这是我的制作文件 -
C_SOURCES = $(wildcard drivers/*.c kernel/*.c)
HEADERS = $(wildcard kernel/*.h drivers/*.h)
OBJ = ${C_SOURCES:.c=.o}
all: os-image
os-image: boot/boot_sector.bin kernel.bin
cat $^ > $@
kernel.bin: kernel/kernel_start.o ${OBJ}
ld -o $@ -Ttext 0x1000 $^ --oformat binary
%.o : %.c
gcc -std=c99 -Wall -pedantic -ffreestanding -c $< -o $@
%.o : %.asm
nasm $< -f elf64 -o $@
%.bin : %.asm
nasm $< -f bin -o $@
clean:
rm -fr kernel/*.o
rm -fr drivers/*.o
rm -fr boot/*.bin
rm -fr os-image *.bin *.o
推荐答案
根据其他答案和评论中建议的更改,您的问题对我来说似乎无法重现.以下代码对我有用.我试图保持您的编码方式,以便对您有意义:
With the changes suggested in other answer and comments, your problem doesn't seem to be reproducible for me. The following code works for me. I've tried to maintain how you coded it just so it makes sense to you:
#define VIDEO_MEM 0xb8000
void write_string( unsigned char colour, const char *string );
void write_string_line( unsigned char colour, const char *string, int pos );
void putChar(char character, short col, short row, unsigned char attr);
/* Place this at top of file as first code in kernel.o */
__asm__ ("call main
"
"cli
"
"hlt
"
);
void main()
{
volatile unsigned char *vid = (unsigned char*) VIDEO_MEM;
int i=0;
for (i = 0; i < 2000; i++)
{
*vid = ' ';
*(vid+1) = 0x1f;
vid += 2;
}
write_string(0x1f,"The Kernel has been loaded successfully!!");
write_string_line(0x1f,"Testing Here!!",1);
putChar('Z',3,3,0xf3);
}
void write_string( unsigned char colour, const char *string ) {
volatile unsigned char *vid = (unsigned char*) VIDEO_MEM;
while(*string != 0)
{
*(vid) = *string;
*(vid+1) = colour;
++string;
vid+=2;
}
}
void write_string_line( unsigned char colour, const char *string, int pos ) {
volatile unsigned char *vid = (unsigned char*) VIDEO_MEM;
vid+=pos*160;
while(*string != 0)
{
*vid = *string;
*(vid+1) = colour;
++string;
vid+=2;
}
}
void putChar(char character, short col, short row, unsigned char attr) {
volatile unsigned char* vid_mem = (unsigned char *) VIDEO_MEM;
int offset = (row*80 + col)*2;
vid_mem += offset;
if(!attr) {
attr = 0x0f;
}
*(unsigned short int *)vid_mem = (attr<<8)+character;
/* This would do the same as line above
*vid_mem = character;
*(vid_mem+1) = attr;
*/
}
我在开头添加了 __asm__
以确保代码首先出现在生成的目标文件中.没有它它可能会工作.我已将您所有的 *vid
指针修改为 volatile
.由于视频是内存映射 IO,您不希望编译器在优化时可能删除屏幕写入.很可能您的代码在没有 volatile
的情况下也能工作,但在此处添加它以避免潜在问题是合适的.
I've added the __asm__
at the beginning to make sure that code is the first to appear in the generated object file. It likely works without it. I've modified all your *vid
pointers to be volatile
. Since video is memory mapped IO you don't want to have the compiler potentially remove screen writes when it optimizes. Likely your code will work without volatile
, but it is proper to add it here to avoid potential problems.
当运行 BOCHS 时,这段代码会产生这个屏幕输出:
When run BOCHS this code produces this screen output:
如果您使用此处提供的代码但它不起作用,则表明您遇到的问题可能与您在引导加载程序中编写的读取磁盘、启用 A20、设置 GDT、输入保护的代码有关模式,然后调用您的 C 代码.根据您编译和链接内核的方式,也可能出现问题.
If you use the code provided here and it doesn't work that would suggest the issue you are having is likely related to the a code you write in your bootloader that read the disk, enabled A20, set the GDT, entered protected mode, and then called into your C code. It is also possible problems could occur depending on how you compile and link your kernel.
在 EDIT 2 中提供了所有代码和 make 文件之后,很明显一个重大问题是大部分代码被编译并链接到 64 位对象和可执行文件.该代码在 32 位保护模式下不起作用.
After all the code and the make file were made available in EDIT 2 it became clear that one significant problem was that most of the code was compiled and linked to 64-bit objects and executables. That code won't work in 32-bit protected mode.
在 make 文件中进行这些调整:
In the make file make these adjustments:
- 使用GCC编译时需要添加
-m32
选项 - 当使用 GNU Assembler (as) 组装面向 32 位对象时,您需要使用
--32
- 当与LD链接时,你需要添加
-melf_i386
选项 - 当使用 NASM 组装面向 32 位对象时,您需要将
-f elf64
更改为-f elf32
- When compiling with GCC you need to add
-m32
option - When assembling with GNU Assembler (as) targeting 32-bit objects you need to use
--32
- When linking with LD you need to add the
-melf_i386
option - When assembling with NASM targeting 32-bit objects you need to change
-f elf64
to-f elf32
从宿主环境使用 64 位编译器和工具链的一个更好的选择是创建一个 i686 或 i386 的交叉编译器工具链.
A preferable option to using a 64-bit compiler and tool chain from the host environment is to create a cross compiler toolchain for i686 or i386.
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