从多个文件的 grep 搜索中获取最后一行 [英] get last line from grep search on multiple files

问题描述

我目前在使用 grep 命令时遇到了一些问题.

I'm curently having some problem with a grep command.

我找到了只显示 grep 搜索的最后一行的方法:

I've found the way to only show the last line of a grep search :

grep PATERN FILE_NAME | tail -1

我还找到了在多个选定文件中进行 grep 搜索的方法:

I also find the way to make a grep search in multiple selected files :

find . -name "FILE_NAME" | xargs -I name grep PATERN name

现在我只想获取每个文件的 grep 结果的最后一行.我试过这个:

Now I would like to only get the last line of the grep result for each single file. I tried this :

 find . -name "FILE_NAME" | xargs -I name grep PATERN name | tail -1

这仅返回最后一个文件的最后一个值，我希望每个文件都有最后一个匹配模式.

This returns me only the last value of the last file where I would like to have the last matching patern for every file.

推荐答案

for f in $(find . -name "FILE_NAME"); do grep PATTERN $f | tail -1; done

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