获取grep匹配后的下一个单词 [英] get the next word after grep matching

问题描述

我正在使用此命令来检索连接到接入点的客户端的信号平均功率:

I'm using this command to retrieve the signal average power of a client connected to an Access Point:

iw dev wlan0 station dump | grep -E 'Station|signal avg': 

我得到以下信息:

站my_MAC_Address"(在 wlan0 上)

Station "my_MAC_Address" (on wlan0)

信号平均值: -46 dBm

粗体是我与 grep 匹配的内容，我只想得到匹配后的单词，即 MAC 地址和数字 -46.我一直在玩 awk 但没有成功.希望你能帮助我！

In bold is what I matches with grep and I just only want to get the word after that matching, i.e the MAC address and the number -46. I've been playing with awk but without success. hope you can help me!

推荐答案

iw dev wlan0 station dump | grep -Po '(?<=Stations|signal avg:s)[^s]*'

这个正则表达式使用所谓的lookbehind 语法.你可以在这里

This regexp uses a so-called lookbehind syntax. You can read about it here

示例输出:

00:11:22:33:44:55
-40

更新:

感谢您对这个答案投票.现在我知道另一个解决方案:

Update:

Thanks for voting this answer up. Now I know another solution:

iw dev wlan0 station dump | grep -Po '(Stations|signal avg:s)K[^s]*'

这实际上是上述解决方案的简写.K 基本上意味着在它发生之前忘记一切".

Which is actually a shorthand for the solution above. K basically means "forget everything before its occurance".

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