如何在两个文件中搜索重复的用户，然后打印这些行? [英] How to search duplicate users in two files and then print those lines?

问题描述

我有两个文件:FILE1 和 FILE2:文件1:

I have two files: FILE1 and FILE2: FILE1:

user1        1.1.1.1
user2        2.2.2.2
user3        3.14.14.3
user4        4.4.4.4
user5        198.222.222.222

文件 2

user1        99.22.54.214
user66       45.22.88.88
user99       44.55.66.66
user4        8.8.8.8
user39       54.54.54.54
user2        2.2.2.2

输出文件

user1        1.1.1.1
user1        99.22.54.214
user2        2.2.2.2
user4        4.4.4.4
user4        8.8.8.8

我尝试了 for 循环，但特别成功.任何人都可以为此写一个代码吗?谢谢！

I tried with a for loop but with particular succes.. Can anyone write me a code for this? Thx!

推荐答案

我可能遗漏了一些东西，但我认为排序独特"应该给出正确的答案.

I might be missing something, but I'd think a "sort unique" should give the right answer.

$ sort -u file1 file2
user1        1.1.1.1
user1        99.22.54.214
user2        2.2.2.2
user3        3.14.14.3
user39       54.54.54.54
user4        4.4.4.4
user4        8.8.8.8
user5        198.222.222.222
user66       45.22.88.88
user99       44.55.66.66

当然，除非您提供的输出文件是您期望的整个输出.由于您没有提及从输出中消除行的任何内容，因此我假设您想要所有这些行.

Unless, of course, the output file you provided is the entire output you expect. Since you didn't say anything about eliminating lines from the output, I'll assume you want all of them.

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