从字符串中获取文本的特定部分 [英] Grabbing specific sections of text from a string

问题描述

我有一个字符串，我需要从中提取两个部分 - 它们各不相同，因为它是一个 PHP 语言文件.希望有人能帮忙，字符串是:

I've got a string that I need to grab two section out - they vary as it's a PHP language file. Hoping someone can help, the string is:

$_LANG['FIELD1'] = "FIELD2";

我需要获取 FIELD1 和 FIELD2

I need to grab FIELD1 and FIELD2

推荐答案

应该这样做:

# space seperated
$ sed -n "s/.*_LANG['([^']*)'] = .(w*).*/1 2/p" file
FIELD1 FIELD2

# newline seperated 
$ sed -n "s/.*_LANG['([^']*)'] = .(w*).*/1
2/p" file
FIELD1
FIELD2

或者将 grep 与 positive lookbehind 结合使用::>

Or using grep with positive lookbehind:

$ grep -Po "(?<=_LANG[')[^']*" file
FIELD1

$ grep -Po '(?<=_LANG[.FIELD1.] = ")[^"]*' file
FIELD2

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