Android:创建一个具有多个选择选项的弹出窗口 [英] Android: create a popup that has multiple selection options

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问题描述

我一直在四处寻找,试图弄清楚如何创建一个有 4 个选项可供选择的弹出窗口或对话框.

I've been searching around trying to figure out how to create a popup or a dialog that has 4 options to choose from.

我在 Android 开发者网站上看到这张图片:

I see this picture on the Android developer site:

有谁知道如何编写类似于右侧的代码?我的文本旁边不需要任何图标,我只需要能够从 4 个选项中进行选择.

Does anyone know how to code up something like the one on the right? I don't need any icons next to my text, I just need to be able to select from 4 options.

推荐答案

您可以创建一个 String 数组,其中包含要在其中显示的选项,然后将该数组传递给 AlertDialog.Builder 使用方法 setItems(CharSequence[], DialogInterface.OnClickListener).

You can create a String array with the options you want to show there and then pass the array to an AlertDialog.Builder with the method setItems(CharSequence[], DialogInterface.OnClickListener).

示例:

String[] colors = {"red", "green", "blue", "black"};

AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setTitle("Pick a color");
builder.setItems(colors, new DialogInterface.OnClickListener() {
    @Override
    public void onClick(DialogInterface dialog, int which) {
        // the user clicked on colors[which]
    }
});
builder.show();

输出(在 Android 4.0.3 上):

The output (on Android 4.0.3):

(不包括背景图.;))

(Background map not included. ;))

这篇关于Android:创建一个具有多个选择选项的弹出窗口的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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