Spring+Hibernate 中的@Transactional [英] @Transactional in Spring+Hibernate
问题描述
我在我的 Web 应用程序中使用 Spring 3.1 + Hibernate 4.x.在我的 DAO 中,我将用户类型对象保存如下
I an using Spring 3.1 + Hibernate 4.x in my web application. In my DAO, i am saving User type object as following
sessionFactory.getCurrentSession().save(user);
但得到以下异常:
org.hibernate.HibernateException: save is not valid without active transaction
我用谷歌搜索并发现了类似的问题 在 SO 上,使用以下解决方案:
I googled and found similar question on SO, with following solution:
Session session=getSessionFactory().getCurrentSession();
Transaction trans=session.beginTransaction();
session.save(entity);
trans.commit();
这就解决了问题.但是在那个解决方案中,手动开始和提交事务有很多混乱.
That solves the problem. But in that solution, there is lot of mess of beginning and committing the transactions manually.
我不能直接使用 sessionFactory.getCurrentSession().save(user);
而无需手动开始/提交事务吗?
Can't i use sessionFactory.getCurrentSession().save(user);
directly without begin/commit of transactions manually?
我也尝试在我的服务/dao 方法上使用 @Transactional
,但问题仍然存在.
I try to use @Transactional
on my service/dao methods too, but the problem persists.
这是我的 Spring 配置文件:
EDIT : Here is my Spring Config File:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.1.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-3.1.xsd">
<!-- enable the configuration of transactional behavior based on annotations -->
<tx:annotation-driven transaction-manager="txManager"/>
<bean id="dataSource"
class="org.springframework.jdbc.datasource.DriverManagerDataSource"
p:driverClassName="${db.driverClassName}" p:url="${db.url}"
p:username="${db.username}" p:password="${db.password}" />
<bean id="sessionFactory"
class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="com.myapp.entities" />
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="txManager"
class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory">
<ref bean="sessionFactory" />
</property>
</bean>
</beans>
我正在使用以下 Hibernate 4 依赖项:
I am using following Hibernate 4 dependencies:
<!-- Hibernate Dependency -->
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-core</artifactId>
<version>4.1.7.Final</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-entitymanager</artifactId>
<version>4.1.1.Final</version>
</dependency>
<dependency>
<groupId>cglib</groupId>
<artifactId>cglib</artifactId>
<version>${cglib.version}</version>
<scope>runtime</scope>
</dependency>
请帮忙.
推荐答案
我认为您正在使用 Hibernate 4.x 那么为什么您在应用程序上下文文件中使用 Hibernate 3 事务管理器?
i think you are using Hibernate 4.x then why you are using hibernate 3 transaction manager in application context file?
<bean id="txManager"
class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory">
<ref bean="sessionFactory" />
</property>
</bean>
我觉得应该是
<bean id="txManager"
class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="sessionFactory">
<ref bean="sessionFactory" />
</property>
</bean>
尝试使用 hibernate 4 事务管理器以及它应该可以工作的 @Transactional 属性.
just try to use hibernate 4 transaction manager along with @Transactional attribute it should work.
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