布尔字段的 JSON Post 请求默认发送 false [英] JSON Post request for boolean field sends false by default

问题描述

我正在使用 FireFox RestClient 发送 JSON Post 请求.

Hi I am sending a JSON Post request using the FireFox RestClient.

我的 JSON 请求如下:

My JSON Request is as below:

 { "firstName": "Test", "lastName": "1", "isActive": 1 }

我的 POJO 有如下的 isActive 字段

My POJO has isActive field as below

  private boolean isActive;

我的控制器定义如下

@RequestMapping(method = {RequestMethod.POST, 
                                 RequestMethod.PUT}, value = "/save")
public ResponseEntity<RestResponse> save(
      @RequestBody POJOUserDetails userDetails, WebRequest request){

在我的 POJO 中，当我检查 isActive 的值时，无论我发送什么都是假的.我在我的 JSON 请求中尝试了以下值

In my POJO, when I check the value of isActive, it is false no matter what I send. I tried below value in my JSON request

"isActive": 1
"isActive": true 
"isActive": "true"
"isActive": ""
"isActive": null
"isActive": false

以上所有内容都在我的控制器中发送错误.请帮忙.谢谢

All of above sends false in my controller. Please help. Thanks

添加 POJO 详细信息

Adding POJO details

@JsonIgnoreProperties(ignoreUnknown = true)
@JsonSerialize(include=Inclusion.NON_EMPTY)
public class POJOUserDetails {
private String firstName;
private String lastName;
private boolean isActive;

public boolean isActive() {
    return isActive;
}
public void setActive(boolean isActive) {
    this.isActive = isActive;       
}

    public String getFirstName() {
    return firstName;
}
public void setFirstName(String firstName) {
    this.firstName = firstName;
}
public String getLastName() {
    return lastName;
}
public void setLastName(String lastName) {
    this.lastName = lastName;
}   
}

推荐答案

请记住，默认情况下，Jackson 从 getter 或 setter(第一个匹配的)确定属性名称.

Remember that Jackson, by default, determines the property name from either the getter or setter (the first that matches).

要反序列化 POJOUserDetails 类型的对象，Jackson 将查找三个属性

To deserialize an object of type POJOUserDetails, Jackson will look for three properties

public void setFirstName(String firstName) {

public void setLastName(String lastName) {

public void setActive(boolean isActive) {

在 JSON 中.这些基本上是firstName、lastName、active.

in the JSON. These are basically firstName, lastName, active.

你得到以下 JSON

{ "firstName": "Test", "lastName": "1", "isActive": 1 }

因此 firstName 和 lastName 已映射，但您没有名为 isActive 的属性.

So firstName and lastName are mapped, but you don't have a property named isActive.

Jackson 依赖于 Java Bean 命名约定及其访问器(getter)和修改器(setter).对于像

Jackson depends on Java Bean naming conventions with their accessors (getters) and mutators (setters). For a field like

private boolean isActive;

合适的 setter/getter 名称是

the appropriate setter/getter names are

public boolean getIsActive() {
    return isActive;
}

public void setIsActive(boolean isActive) {
    this.isActive = isActive;
}

所以你有两种可能的解决方案.如上所示更改您的 getter/setter 或使用 @JsonProperty 注释您的字段，以便 Jackson 使用字段名称来确定属性名称

So you have two possible solutions. Change your getter/setter as shown above or annotate your field with @JsonProperty so that Jackson uses the field name to determine the property name

@JsonProperty
private boolean isActive;

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