.NET LDAP 路径实用程序 (C#) [英] .NET LDAP paths utilities (C#)

问题描述

是否有用于 LDAP 路径操作的 .NET 库?
我想要一些等效于 System.IO.Path 的东西，允许例如做类似的事情

Is there a .NET library for LDAP paths manipulations?
I would like to have something equivalent to System.IO.Path, allowing e.g. to do something like

string ou1 = LDAPPath.Combine("OU=users","DC=x,DC=y");
string ou2 = LDAPPath.Parent("CN=someone,OU=users,DC=x,DC=y");

否则，在 .NET 中处理 LDAP 专有名称的常用方法是什么?

Otherwise, what's the common way to deal with LDAP distinguished names in .NET?

澄清我的问题:我一般不问.NET 中的目录服务"；我已经使用它并完成了一些程序来执行一些任务.我觉得缺少的是操作路径、解析可分辨名称等的正确方法，并且由于这应该是一个非常普遍的需求，我希望有一种比拆分字符串更简洁的方法来做到这一点逗号(1).

To clarify my question: I'm not asking about "directory services in .NET" in general; I've already worked with that and done some programs to perform some tasks. What I feel is missing is a proper way to manipulate paths, parse distinguished names and so on, and since this should be a pretty common need, I hope there's a cleaner way to do this than split a string on commas(1).

(1) 例如，调用库中的函数以逗号分隔字符串

(1) like, for example, calling a function in a library that splits the string on commas

推荐答案

不，据我所知 - 即使在用于 Active Directory 的最新 .NET 3.5 命名空间中也不行.

No, not to my knowledge - not even in the most recent .NET 3.5 namespace for Active Directory.

您可以在目录本身中导航层次结构(转到父级等) - 但您需要绑定到例如Active Directory 通过 DirectoryEntry.

You can navigate the hierarchy (going to the parent etc.) in the directory itself - but you need to be bound to e.g. Active Directory by means of a DirectoryEntry.

然后是 NameTranslate API，但这确实是更多的是将此名称更改为另一个名称"，例如从用户主体名称更改为相关 DN - 同样，它需要连接到 AD 中的 DirectoryEntry.

我对找到这样一个库最感兴趣，但到目前为止，我还没有听说过一个 - 无论是在 .NET 中，还是在任何其他语言中，真的.

I would be most interested in finding such a library, but so far, I haven't heard about one - neither in .NET nor in any other language, really.

回到我的重型" AD 编程时代，我有自己的一套 LDAP 路径操作例程(在 Delphi 中)——基本上只是字符串解析和处理.

Back in my "heavy-duty" AD programming days, I had my own set of LDAP path manipulation routines (in Delphi) - basically just string parsing and handling.

马克

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