无需参考即可查找 UIAlertView iOS 7 [英] Find UIAlertView without having reference to it iOS 7

问题描述

我在我的项目中使用了一个代码片段，在这里回答:UIAlertView而没有参考它

I was using a code snippet in my project answered here: UIAlertView without having reference to it

代码如下:

+ (UIAlertView *) getUIAlertViewIfShown {
    if ([[[UIApplication sharedApplication] windows] count] == 1) {
        return nil;
    }

    UIWindow *window = [[[UIApplication sharedApplication] windows] objectAtIndex:1];
    if ([window.subviews count] > 0) {
        UIView *view = [window.subviews objectAtIndex:0];
        if ([view isKindOfClass:[UIAlertView class]]) {
            return (UIAlertView *) view;
        }
    }
    return nil;
}

不幸的是，它在 iOS 7 中不起作用，我无法关闭警报视图.在调试时，我发现在循环中它显示该视图属于 UITransitionView 类.非常令人困惑，因为我找不到有关此视图类的任何快速文档.

Unfortunately its not working in iOS 7 and I'm unable to dismiss an alert view. While debugging I found that in the loop its showing that view is of class UITransitionView. Pretty confusing because I couldn't find any quick documentation for this view class.

有什么想法可以解决这个问题吗?

Any ideas how can I fix this problem?

推荐答案

在iOS7中，UIAlertView窗口不会出现在-[UIApplication windows]中.事实上，UIAlertView 本身从来没有被添加到任何窗口中，-[UIAlertView window] 总是nil.相反，警报视图管理放置在 -[UIApplication keyWindow] 中的各种未记录的视图，而不引用回警报视图.

In iOS7, the UIAlertView window does not appear in -[UIApplication windows]. In fact, the UIAlertView itself is never added to any window, -[UIAlertView window] is always nil. Instead, the alert view manages a variety of undocumented views placed in -[UIApplication keyWindow] with no reference back to the alert view.

您在 iOS7 中唯一真正的选择是实际跟踪您的警报视图.

Your only real option in iOS7 is to actually keep track of your alert views.

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