Django StreamingHttpResponse 到模板中 [英] Django StreamingHttpResponse into a Template

问题描述

Django 1.5 刚刚发布并提供了 StreamingHttpResponse.现在，我已经阅读了这个讨论和第二个答案打印出页面中的流(实际上只是数据).

Django 1.5 is just came out and it ships the StreamingHttpResponse. Now, I've read this discussion and the second answer actually prints out the stream in a page (actually just data).

我想要做的是将流响应的输出打印到模板中，而不仅仅是像 讨论.

What I want to do is to print the output of a stream response into a template, not just print the data as in the discussion.

我该怎么办?我是否必须使用 javascript 并调用实现 StreamingHttpResponse 的视图，或者有一种方法可以告诉 django 呈现模板，然后将 StreamingHttpResponse 数据发送到模板(然后我需要知道存储数据的变量是什么)?

What should I do? do I've to use javascript and call the view that implements the StreamingHttpResponse, or there's a way to tell django to render the template and later send the StreamingHttpResponse data to the template (then I need to know what's the variables where data are stored)?

目前我找到的解决方案是将最终 html 页面的片段写入生成器(yield).这个解决方案的问题是，例如，我不能有一个随着数据流而增长的条(如加载条).

the solution I found so far is to write the pieces of the final html page into the generator (yield). The problem of this solution is that I can't have, for example, a bar that grows with the data streamed (like a loading bar).

呸

推荐答案

是的，但它可能不是你真正想要的，因为整个模板都会被迭代.但是，无论如何，您可以为模板流式传输重新渲染的上下文.

Yes, but it may not be what you really want, as the entire template will be iterated. However, for what it's worth, you can stream a re-rendered context for a template.

from django.http import StreamingHttpResponse
from django.template import Context, Template

#    Template code parsed once upon creation, so
#        create in module scope for better performance

t = Template('{{ mydata }} <br />
')

def gen_rendered():
    for x in range(1,11):
        c = Context({'mydata': x})
        yield t.render(c)

def stream_view(request):
    response = StreamingHttpResponse(gen_rendered())
    return response

编辑:你也可以渲染一个模板，然后在它上面附加

或 标签，但这与模板的初衷背道而驰.(即从代码中分离展示)

EDIT: You can also render a template and just append <p> or <tr> tags to it, but it's quite contrary to the purpose of templates in the first place. (i.e. separating presentation from code)

from django.template import loader, Context
from django.http import StreamingHttpResponse

t = loader.get_template('admin/base_site.html') # or whatever
buffer = ' ' * 1024

def gen_rendered():  
    yield t.render(Context({'varname': 'some value', 'buffer': buffer}))
    #                                                 ^^^^^^
    #    embed that {{ buffer }} somewhere in your template 
    #        (unless it's already long enough) to force display

    for x in range(1,11):
        yield '<p>x = {}</p>{}
'.format(x, buffer)

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