Android AsyncTask 不返回正确的结果 [英] Android AsyncTask don't return correct Result

问题描述

对于我想将 Ksoap 与 AsyncTask 一起使用的项目之一.现在在下面的代码中 AsyncTask 可以正常工作，但在将结果返回给 WSDLHeper 后，我得到了错误的值.例如 doInBackground 方法中 this.result 的结果是:

for one of projects i want to use Ksoap with AsyncTask. now in this below code AsyncTask can work correctly but after return result to WSDLHeper i get wronge value. for example Result for this.result in doInBackground method is :

[1, 4674070, {item=3000738; item=TSMS; item=30007227; item=30004444440000; item=30007227001401; item=50004066569100; item=50001717; item=500017171; item=5000171717; item=50001717007227; }]

返回值后我在 tmp = String.valueOf(p.execute()) 有:

ir.tsms.wsdl.ProcessTask@417b65e0

在这一行:

tmp = String.valueOf(p.execute());

那就错了 tmp 必须有

[1, 4674070, {item=3000738; item=TSMS; item=30007227; item=30004444440000; item=30007227001401; item=50004066569100; item=50001717; item=500017171; item=5000171717; item=50001717007227; }]

返回.

我的代码:

public class WSDLHelper {
    public SoapObject request;
    public static String call(SoapObject rq){

        String tmp;
        ProcessTask p =new ProcessTask(rq);

        tmp = String.valueOf(p.execute());

        return tmp;
    }

}
class ProcessTask extends AsyncTask<Void, Void, String > {
    SoapObject req1;
    private String result;
    public ProcessTask(SoapObject rq) {
        req1 = rq;
    }

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
    }

    @Override
    protected String doInBackground(Void... params) {

        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.setOutputSoapObject(this.req1);

        AndroidHttpTransport transport = new AndroidHttpTransport(Strings.URL_TSMS);
        transport.debug = true;

        try {
            transport.call(Strings.URL_TSMS + this.req1.getName(), envelope);
            this.result = envelope.getResponse().toString();
        } catch (IOException ex) {
            Log.e("" , ex.getMessage());
        } catch (XmlPullParserException ex) {
            Log.e("" , ex.getMessage());
        }

        if (result.equals(String.valueOf(Integers.CODE_USER_PASS_FALSE))) {
            try {
                throw new TException(PublicErrorList.USERNAME_PASSWORD_ERROR);
            } catch (TException e) {
                e.printStackTrace();
            }

            return null;
        }
        return this.result;
    }

    @Override
    protected void onPostExecute(String result) {

        super.onPostExecute(result);
    }

}

推荐答案

你无法通过

tmp = String.valueOf(p.execute());

这是因为 Android 应用不会等待 AsyncTask 返回值以移动到下一行.

This is because Android app doesn't wait for AsyncTask to return a value to move to next line.

您需要使用 onPostExecute() 方法来处理 AsyncTask 的返回值.

You need to use the onPostExecute() Method to process the return value of an AsyncTask .

可以参考AsyncTask:doInBackground()的返回值去哪里了? 了解更多语法和更多信息.

You can refer AsyncTask: where does the return value of doInBackground() go? for more syntax and more information.

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