如何确保分区具有来自因子每个级别的代表性观察? [英] How can I ensure that a partition has representative observations from each level of a factor?

问题描述

我编写了一个小函数来将我的数据集划分为训练集和测试集.但是，我在处理因子变量时遇到了麻烦.在我的代码的模型验证阶段，如果模型建立在没有来自每个因子级别的表示的数据集上，我会收到错误消息.如何修复此 partition() 函数以包含来自因子变量每个级别的至少一个观察结果?

I wrote a small function to partition my dataset into training and testing sets. However, I am running into trouble when dealing with factor variables. In the model validation phase of my code, I get an error if the model was built on a dataset that doesn't have representation from each level of a factor. How can I fix this partition() function to include at least one observation from every level of a factor variable?

test.df <- data.frame(a = sample(c(0,1),100, rep = T),
                      b = factor(sample(letters, 100, rep = T)),
                      c = factor(sample(c("apple", "orange"), 100, rep = T)))

set.seed(123)
partition <- function(data, train.size = .7){
  train <- data[sample(1:nrow(data), round(train.size*nrow(data)), rep= FALSE), ]
  test <- data[-as.numeric(row.names(train)), ]
  partitioned.data <- list(train = train, test = test)
  return(partitioned.data)
}

part.data <- partition(test.df)
table(part.data$train[,'b'])
table(part.data$test[,'b'])

EDIT - 使用caret"包和 createDataPartition() 的新函数:

EDIT - New function using 'caret' package and createDataPartition():

partition <- function(data, factor=NULL, train.size = .7){
  if (("package:caret" %in% search()) == FALSE){
    stop("Install and Load 'caret' package")
  }
  if (is.null(factor)){
    train.index <- createDataPartition(as.numeric(row.names(data)),
                                       times = 1, p = train.size, list = FALSE)
    train <- data[train.index, ]
    test <- data[-train.index, ]
  }
  else{
    train.index <- createDataPartition(factor,
                                       times = 1, p = train.size, list = FALSE)
    train <- data[train.index, ]
    test <- data[-train.index, ]
  }
  partitioned.data <- list(train = train, test = test)
  return(partitioned.data)
}

推荐答案

试试 caret 包，特别是 createDataPartition() 函数.它应该完全符合您的需要，可在 CRAN 上找到，主页在这里:

Try the caret package, particularly the function createDataPartition(). It should do exactly what you need, available on CRAN, homepage is here:

caret - 数据拆分

我提到的函数部分是我在网上找到的一些代码，然后我稍微修改了它以更好地处理边缘情况(例如，当您要求的样本大小大于集合或子集时).

The function I mentioned is partially some code I found a while back on net, and then I modified it slightly to better handle edge cases (like when you ask for a sample size larger than the set, or a subset).

stratified <- function(df, group, size) {
  # USE: * Specify your data frame and grouping variable (as column
  # number) as the first two arguments.
  # * Decide on your sample size. For a sample proportional to the
  # population, enter "size" as a decimal. For an equal number
  # of samples from each group, enter "size" as a whole number.
  #
  # Example 1: Sample 10% of each group from a data frame named "z",
  # where the grouping variable is the fourth variable, use:
  #
  # > stratified(z, 4, .1)
  #
  # Example 2: Sample 5 observations from each group from a data frame
  # named "z"; grouping variable is the third variable:
  #
  # > stratified(z, 3, 5)
  #
  require(sampling)
  temp = df[order(df[group]),]
  colsToReturn <- ncol(df)

  #Don't want to attempt to sample more than possible
  dfCounts <- table(df[group])
  if (size > min(dfCounts)) {
    size <- min(dfCounts)
  }



  if (size < 1) {
    size = ceiling(table(temp[group]) * size)
  } else if (size >= 1) {
    size = rep(size, times=length(table(temp[group])))
  }
  strat = strata(temp, stratanames = names(temp[group]),
                 size = size, method = "srswor")
  (dsample = getdata(temp, strat))

  dsample <- dsample[order(dsample[1]),]
  dsample <- data.frame(dsample[,1:colsToReturn], row.names=NULL)
  return(dsample)

}

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