如何使用 Google Cloud 功能获取 URL?要求? [英] How to fetch a URL with Google Cloud functions? request?
问题描述
我将 Google Apps 脚本用于
I used Google Apps Script with
var response = UrlFetchApp.fetch(url, params);
从 api 获得响应.遗憾的是,我需要使用 Drive 中的 Google Apps 脚本处理太多的请求和太多的数据
to get a response from an api. Sadly its too many request and too many data i need to be handled with Google Apps Script in Drive
我现在的想法是切换到谷歌云功能和请求,但它不起作用.
My idea was now to switch to Google cloud functions and request but its not working.
const request = require('request');
const headers = {
"Authorization" : "Basic " + Buffer.from('blabla').toString('base64')
};
const params = {
"method":"GET",
"headers":headers
};
exports.getCheckfrontBookings = (req, res) => {
let url = 'https://fpronline.checkfront.com/api/3.0/item'
request({url:url, qs:params}, function(err, response, body) {
if(err) { console.log(err); return; }
console.log("Get response: " + response.statusCode);
});
推荐答案
request
原生支持回调接口,但不返回 Promise,这是您必须在 Cloud Function 中执行的操作.
request
supports callback interfaces natively but does not return a promise, which is what you must do within a Cloud Function.
您可以使用 request-promise
(https://github.com/request/request-promise) 和 rp(...)
方法返回符合常规 Promises/A+ 的承诺",然后执行以下操作:
You could use request-promise
(https://github.com/request/request-promise) and the rp(...)
method which "returns a regular Promises/A+ compliant promise" and then do something like:
const rp = require('request-promise');
exports.getCheckfrontBookings = (req, res) => {
var options = {
uri: 'https://fpronline.checkfront.com/api/3.0/item',
headers: {
Authorization: 'Basic ' + Buffer.from('blabla').toString('base64')
},
json: true // Automatically parses the JSON string in the response
};
rp(options)
.then(response => {
console.log('Get response: ' + response.statusCode);
res.send('Success');
})
.catch(err => {
// API call failed...
res.status(500).send('Error': err);
});
};
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