配置 MSBuild 输出路径 [英] Configure MSBuild output path

问题描述

有一个带有本地化资源文件的 Windows 窗体 (NET 3.5) 项目 foo.csproj.我使用 MSBuild 构建项目并创建部署结构:

There is a Windows Forms (NET 3.5) project, foo.csproj, with localized resources files. I use MSBuild to build the project and create a deployment structure:

<MSBuild Projects="foo.csproj" Properties="Configuration=Release;OutputPath=..deployfoo" Targets="Build" />

它将 foo.exe 和所有本地化的 DLL 文件复制到 deployfoo 文件夹，但我需要将本地化的 DLL 文件复制到单独的文件夹中.应该是:

It copies foo.exe and all localized DLL files to the deployfoo folder, but I need localized DLL files to be copied into a separate folder. It should be:

• 部署foofoo.exe
• 部署locales u-RUfoo.resources.dll
• 部署localespt-BRfoo.resources.dll

有没有办法配置 MSBuild 将 EXE 和 DLL 文件复制到不同的文件夹?

Is there a way to configure MSBuild to copy EXE and DLL files to different folders?

推荐答案

资源文件的生成和复制在构建期间在内部 MSBuild 过程中完成:GenerateSatelliteAssemblies 和 CopyFilesToOutputDirectory.它们被复制到输出目录中.

Resource files generation and copy is done in an internal MSBuild process during the build: GenerateSatelliteAssemblies and CopyFilesToOutputDirectory. They are copied in the output directory.

据我所知，您无法修改此行为.

As far as I know, you can't modify this behavior.

您必须在构建步骤之后移动资源文件.我建议使用 MSBuild 社区任务中的 Move 任务.

You have to move your resources files after the build step. I would advise to use the Move task from MSBuild community tasks.

<MSBuild Projects="foo.csproj" Properties="Configuration=Release;OutputPath=..deployfoo" Targets="Build" />

<CreateItem Include="..deployfoo***.resources.dll">
    <Output TaskParameter="Include" ItemName="ResourcesToMove" />
</CreateItem>

<Move SourceFiles="@(ResourcesToMove)" DestinationFiles="@(ResourcesToMove->'..deploylocales\%(RecursiveDir)\%(Filename)%(Extension)')"/>

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