android phonegap 相机和图像上传 [英] android phonegap camera and image uploading

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本文介绍了android phonegap 相机和图像上传的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

自周五以来,我一直在努力完成这项工作,搜索了谷歌和这里.我的最终目标是能够拍摄多张带有标题和描述的照片,并将它们上传到服务器,然后显示在网页上.

I have been trying to make this work, searched google and here since Friday. My ultimate goal is to be able take multiple pictures with a title and description for each and upload them to a server, then display on a web page.

目前我所拥有的是:为一张图片指定标题和描述、浏览图库、查找图片并选择它的能力.但是当我这样做时,图像会立即与表单一起上传.我希望能够使用提交按钮来执行此操作.

What I have so far is: the ability to give one image a title and description, browse the gallery, find an image and select it. BUT when I do the image is uploaded along with the form, immediately. I would like to be able to do this using a submit button.

我也有一个按钮来代替拍摄图像,并在页面上显示图像的预览.但是当我用相机拍照时,我不知道如何上传我的表格.我能够使用 div 和 innerHTML 调用将图像数据打印到屏幕上......但老实说,我很迷茫,甚至不知道从哪里开始发布特定的代码片段.我将发布整个页面,因为它目前存在....

I also have a button to take an image instead, and a preview of the image on the page appears. BUT when I do take an image with the camera I do not know how to upload my form. I was able to print to the screen the image data using a div and innerHTML call... but honestly i'm so lost and do not even know where to start posting specific snippets of code. I will post the entire page as it currently exists right now....

<html>
<head>
    <title>File Transfer Example</title>

    <script type="text/javascript" charset="utf-8" src="cordova-2.3.0.js"></script>
    <script type="text/javascript" charset="utf-8">

        var pictureSource;   // picture source
        var destinationType; // sets the format of returned value

        // Wait for Cordova to load
        //
        document.addEventListener("deviceready", onDeviceReady, false);

        // Cordova is ready
        //
function onDeviceReady() {
    pictureSource=navigator.camera.PictureSourceType;
    destinationType=navigator.camera.DestinationType;
}


        function browse(){
            navigator.camera.getPicture(uploadPhoto,
                                        function(message) { alert('get picture failed'); },
                                        { quality: 50,
                                        destinationType: navigator.camera.DestinationType.FILE_URI,
                                        sourceType: navigator.camera.PictureSourceType.PHOTOLIBRARY }
                                        );
        }

        function uploadPhoto(imageURI) {
            var options = new FileUploadOptions();
            options.fileKey="file";
            options.fileName=imageURI.substr(imageURI.lastIndexOf('/')+1);
            options.mimeType="image/jpeg";

            var params = {};
            params.value1 = "test";
            params.value2 = document.getElementById('file_name').value + "";
            params.value3 = document.getElementById('file_description').value + "";
            options.params = params;

            var ft = new FileTransfer();
            ft.upload(imageURI, encodeURI("http://site.com/pages/upload.php"), win, fail, options);
        }

        function win(r) {
            console.log("Code = " + r.responseCode);
            console.log("Response = " + r.response);
            console.log("Sent = " + r.bytesSent);
        }

        function onFileSystemSuccess(fileSystem) {
            console.log(fileSystem.name);
        }

        function onResolveSuccess(fileEntry) {
            console.log(fileEntry.name);
        }

        function fail(evt) {
            console.log(evt.target.error.code);
        }


        function fail(error) {
            alert("An error has occurred: Code = " + error.code);
            console.log("upload error source " + error.source);
            console.log("upload error target " + error.target);
        }






function capturePhoto() {
  // Take picture using device camera, allow edit, and retrieve image as base64-encoded string  
  navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 20, allowEdit: true,
    destinationType: destinationType.DATA_URL });
}

function onPhotoDataSuccess(imageData) {
  // console.log(imageData);

  var smallImage = document.getElementById('smallImage');
  smallImage.style.display = 'block';
  smallImage.src = "data:image/jpeg;base64," + imageData;

  var smallTEXT = document.getElementById('smallTEXT');
  smallTEXT.style.display = 'block';
  smallTEXT.innerHTML = "data:image/jpeg;base64," + imageData;
}

function onPhotoURISuccess(imageURI) {
  // Uncomment to view the image file URI 
  // console.log(imageURI);

  // Get image handle
  //
  var largeImage = document.getElementById('largeImage');

  // Unhide image elements
  //
  largeImage.style.display = 'block';

  largeImage.src = imageURI;
}
function capturePhoto() {
  // Take picture using device camera and retrieve image as base64-encoded string
  navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 50,
    destinationType: destinationType.DATA_URL });
}



// Called if something bad happens.
// 
function onFail(message) {
  alert('Failed because: ' + message);
}







        </script>
</head>
<body>


    <h1>Example</h1>
    <p>Upload File</p>

    <form name ="filename" id="file_name_form" action="#">
    Title <br><input type="text" name="name" id="file_name" /><br>
    Description <br><textarea type="text" name="description" id="file_description" /></textarea>
    </form>
    <button onclick="capturePhoto();">Use Camera</button> <br>
    <button onclick="browse();">browse gallery</button><br>
    <img style="display:none;width:160px;" id="smallImage" src="" />
    <hr>
    <div id="smallTEXT">ggg</div>
    <button onclick"uploadPhoto();">submit</button>


</body>

推荐答案

根据这个答案:Phonegap android 无法使用 fileTransfer 上传图片不能直接使用 URI....

According to this answer: Phonegap android unable to upload image using fileTransfer You cannot use the URI directly....

但是,好像可以直接使用uri...(见下面我的代码)

But, it seems the uri can be used directly... (see my code below)

编辑 25-7-2013我得到了这个工作:像这样调用:

Edit 25-7-2013 I got this working with: call like this:

navigator.camera.getPicture(onPhotoUriSuccess, onFailCamera, { quality: 50,
        destinationType: pictDestinationType.FILE_URI });

并成功:

function onPhotoUriSuccess(imageUriToUpload){
    var url=encodeURI("http://your_url_for_the_post/");

    var username='your_user';
    var password='your_pwd';

    var params = new Object();
    params.your_param_name = "something";  //you can send additional info with the file

    var options = new FileUploadOptions();
    options.fileKey = "the_name_of_the_image_field"; //depends on the api
    options.fileName = imageUriToUpload.substr(imageUriToUpload.lastIndexOf('/')+1);
    options.mimeType = "image/jpeg";
    options.params = params;
    options.chunkedMode = true; //this is important to send both data and files

    var headers={'Authorization':"Basic " + Base64.encode(username + ":" + password)};
    options.headers = headers;

    var ft = new FileTransfer();
    ft.upload(imageUriToUpload, url, succesFileTransfer, errorFileTransfer, options);

}

顺便说一句,我在 api 站点上使用了一个 apache 网络服务器,我在这里看到,nginx 可能有分块模式的问题:PhoneGap chunckedMode true 上传错误

By the way, I use an apache webserver on the api site, I saw here, nginx could have a problem with the chunked mode: PhoneGap chunckedMode true upload error

这篇关于android phonegap 相机和图像上传的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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