浮点 NaN 有效载荷有什么用途? [英] What uses do floating point NaN payloads have?
问题描述
我知道 IEEE 754 将 NaN 定义为具有以下按位表示:
I know that IEEE 754 defines NaNs to have the following bitwise representation:
- 符号位可以是
0
或1
- 指数字段包含所有
1
位 - 尾数的某些位用于指定它是安静 NaN 还是信号 NaN
- 尾数不能全部为
0
位,因为该位模式保留用于表示无穷大 - 尾数的剩余位构成有效载荷
- The sign bit can be either
0
or1
- The exponent field contains all
1
bits - Some bits of the mantissa are used to specify whether it's a quiet NaN or signalling NaN
- The mantissa cannot be all
0
bits because that bit pattern is reserved for representing infinity - The remaining bits of the mantissa form a payload
当计算的输入为 NaN 时,有效载荷(与整个 NaN 一样)传播到浮点计算的结果,尽管我不知道这种传播的细节或标准是否指定如何这个完成了.谁设置了原始有效载荷?如果我添加两个具有不同负载的 NaN 会发生什么?
The payload is propagated (as is the NaN as a whole) to the result of a floating point calculation when the input of the calculation is NaN, though I have no knowledge of the details of this propagation or whether the standard specifies how this is done. Who sets the original payload? What happens if I add two NaNs with different payloads?
但最重要的是:我以前从未见过使用过 NaN 有效载荷.这个payload字段有什么用?
But most importantly: I've never seen NaN payloads used before. What uses does this payload field have?
推荐答案
在开发 IEEE754 和 NaN 的时候被认为是一个好主意.我实际上已经看到它用于存储创建 NaN 的原因.
It was thought to be a good idea when IEEE754 and NaN's were developed. I have actually seen it used to store the reason why a NaN was created.
今天,出于几个原因,我不会在可移植代码中使用它.你有多确定这个有效载荷会在例如分配中存活下来?如果您指定 x = y,您有多确定 x 与 y 具有相同的 NaN 有效负载?你有多确定它会在算术中存活下来?如果 a 或 b 是 NaN,则 a op b 应该是一个 NaN,或者如果它们都是 NaN,则应该是两个 NaN 之一.确定是这样吗?我不会愿意打赌.
Today, I wouldn't use it in portable code for several reasons. How sure are you that this payload will survive for example an assignment? If you assign x = y, how sure are you that x has the same NaN payload as y? And how sure are you that it will survive arithmetic? If a or b is an NaN, then a op b is supposed to be the one NaN, or one of the two NaNs if they are both NaN. Sure that this is the case? I wouldn't be willing to bet on it.
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