如何修改整数中的位? [英] How to modify bits in an integer?

问题描述

我有一个值为 7 (0b00000111) 的整数，我想用 13 (>0b00001101).替换整数中的位的最佳算法是什么?

I have an integer with a value 7 (0b00000111) And I would like to replace it with a function to 13 (0b00001101). What is the best algorithm to replace bits in an integer?

例如:

set_bits(somevalue, 3, 1) # What makes the 3rd bit to 1 in somevalue?

推荐答案

这些适用于任何大小的整数，甚至大于 32 位:

These work for integers of any size, even greater than 32 bit:

def set_bit(value, bit):
    return value | (1<<bit)

def clear_bit(value, bit):
    return value & ~(1<<bit)

如果你喜欢简短的东西，你可以使用:

If you like things short, you can just use:

>>> val = 0b111
>>> val |= (1<<3)
>>> '{:b}'.format(val)
'1111'
>>> val &=~ (1<<1)
'1101'

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