包含二进制可执行文件的 Bash 脚本 [英] Bash script containing binary executable

问题描述

是否可以编写一个bash脚本，其中包含一个二进制可执行程序?

Is it possible to write a bash script, which would contain a binary executable program inside?

我的意思是一个脚本，它包含一个文本形式的可执行文件的转储，当它被执行时，它会被这个脚本转储回一个可执行文件?

I mean a script, which would contain a dump of an executable in a textual form, which will be dumped back to an executable by this script when it is executed?

我很想知道一个解决方案，它可以开箱即用，无需安装额外的软件包.有可能吗?

I would love to know a solution, which will work out of the box without a need of installing additional packages. Is it possible?

谢谢！

推荐答案

我以前从来没有做过这样的事情 ;)这将编译一些 c 源代码，创建一个包含二进制文件的 b.bash 脚本(以及用于简单开发的原始脚本)

i never done something like this before ;) this will compile some c source, create a b.bash script containing the binary (and the original script for simple development)

(a.bash)

#!/bin/bash

if [ "$0" == "b.bash" ];then
  tail -n +$[ `grep -n '^BINARY' $0|cut -d ':' -f 1` + 1 ] $0 | base64 -d > a2.out
  chmod +x a2.out
  ./a2.out
  echo $?
  exit
fi

cat "$0" > b.bash
echo "BINARY" >> b.bash
cat > a.c << EOF
int     main(){
        return 12;
}
EOF
gcc a.c 
base64 a.out >> b.bash

调用(a.bash 生成 b.bash):

invoke with (a.bash generates b.bash):

bash a.bash ;bash b.bash

我不知道如何避免在执行前将二进制文件写入临时文件...

i don't know how to evade writing out the binary into a temporary file before execution...

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