带有 mod(或模)运算符的 nth-child [英] nth-child with mod (or modulo) operator

问题描述

是否可以将 nth-child 与模一起使用?我知道你可以指定一个公式，比如

Is it possible to use the nth-child with modulo? I know you can specify a formula, such as

nth-child(4n+2)

但我似乎无法找到是否有模运算符.我已经尝试了以下示例，但似乎都不起作用:

But I can't seem to find if there's a modulo operator. I've tried the following examples below, and none seem to work:

nth-child(n%7)
nth-child(n % 7)
nth-child(n mod 7)

推荐答案

不，:nth-child() 只支持加减法和系数乘法.

我猜你正在尝试获取前 6 个元素(因为任何正整数 n 的 n mod 7 只会给你 0 到 6).为此，您可以改用以下公式:

I gather you're trying to pick up the first 6 elements (as n mod 7 for any positive integer n only gives you 0 to 6). For that, you can use this formula instead:

:nth-child(-n+6)

通过否定n，元素计数从零开始倒数，所以这些元素会被选中:

By negating n, element counting is done backwards starting from zero, so these elements will be selected:

 0 + 6 = 6
-1 + 6 = 5
-2 + 6 = 4
-3 + 6 = 3
-4 + 6 = 2
-5 + 6 = 1
...

jsFiddle 演示

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