左联接没有左表中的重复行 [英] Left Join without duplicate rows from left table

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本文介绍了左联接没有左表中的重复行的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

请看下面的查询:

tbl_Contents

Content_Id  Content_Title    Content_Text
10002   New case Study   New case Study
10003   New case Study   New case Study
10004   New case Study   New case Study
10005   New case Study   New case Study
10006   New case Study   New case Study
10007   New case Study   New case Study
10008   New case Study   New case Study
10009   New case Study   New case Study
10010   SEO News Title   SEO News Text
10011   SEO News Title   SEO News Text
10012   Publish Contents SEO News Text

tbl_Media

Media_Id    Media_Title  Content_Id
1000    New case Study   10012
1001    SEO News Title   10010
1002    SEO News Title   10011
1003    Publish Contents 10012

查询

SELECT 
C.Content_ID,
C.Content_Title,
M.Media_Id

FROM tbl_Contents C
LEFT JOIN tbl_Media M ON M.Content_Id = C.Content_Id 
ORDER BY C.Content_DatePublished ASC

结果

10002   New case Study  2014-03-31 13:39:29.280 NULL
10003   New case Study  2014-03-31 14:23:06.727 NULL
10004   New case Study  2014-03-31 14:25:53.143 NULL
10005   New case Study  2014-03-31 14:26:06.993 NULL
10006   New case Study  2014-03-31 14:30:18.153 NULL
10007   New case Study  2014-03-31 14:30:42.513 NULL
10008   New case Study  2014-03-31 14:31:56.830 NULL
10009   New case Study  2014-03-31 14:35:18.040 NULL
10010   SEO News Title  2014-03-31 15:22:15.983 1001
10011   SEO News Title  2014-03-31 15:22:30.333 1002
10012   Publish         2014-03-31 15:25:11.753 1000
10012   Publish         2014-03-31 15:25:11.753 1003

10012 来了两次...!

我的查询从 tbl_Contents(连接中的左表)返回重复行

My query is returning duplicate rows from tbl_Contents (left table in the join)

tbl_Contents 中的某些行在 tbl_Media 中有超过 1 个关联的行.我需要 tbl_Contents 中的所有行,即使 tbl_Media 中存在 Null 值但没有重复记录.

Some rows in tbl_Contents has more than 1 associated rows in tbl_Media. I need all rows from tbl_Contents even if there are Null values exists in the tbl_Media BUT NO DUPLICATE RECORDS.

推荐答案

试试 外部应用

SELECT 
    C.Content_ID,
    C.Content_Title,
    C.Content_DatePublished,
    M.Media_Id
FROM 
    tbl_Contents C
    OUTER APPLY
    (
        SELECT TOP 1 *
        FROM tbl_Media M 
        WHERE M.Content_Id = C.Content_Id 
    ) m
ORDER BY 
    C.Content_DatePublished ASC

或者,您可以GROUP BY结果

SELECT 
    C.Content_ID,
    C.Content_Title,
    C.Content_DatePublished,
    M.Media_Id
FROM 
    tbl_Contents C
    LEFT OUTER JOIN tbl_Media M ON M.Content_Id = C.Content_Id 
GROUP BY
    C.Content_ID,
    C.Content_Title,
    C.Content_DatePublished,
    M.Media_Id
ORDER BY
    C.Content_DatePublished ASC

OUTER APPLY 选择与左表中的每一行匹配的单行(或无).

The OUTER APPLY selects a single row (or none) that matches each row from the left table.

GROUP BY 执行整个连接,但随后折叠提供的列上的最终结果行.

The GROUP BY performs the entire join, but then collapses the final result rows on the provided columns.

这篇关于左联接没有左表中的重复行的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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