在 python 中查找(并保留)子列表的重复项 [英] Find (and keep) duplicates of sublist in python

问题描述

我有一个包含数字的列表(子列表)列表，我只想将它们保留在所有(子)列表中.

I have a list of lists (sublist) that contains numbers and I only want to keep those exists in all (sub)lists.

例子:

x = [ [1, 2, 3, 4], [3, 4, 6, 7], [2, 3, 4, 6, 7]]

output => [3, 4]

我该怎么做?

推荐答案

common = set(x[0])
for l in x[1:]:
    common &= set(l)
print list(common)

或:

import operator
print reduce(operator.iand, map(set, x))

这篇关于在 python 中查找(并保留)子列表的重复项的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！