在 Android 应用程序中读取本地压缩的 XML 文件(gzip) [英] Read local compressed XML file(gzip) in Android application

问题描述

我不知道如何从本地存储的 gzip xml 文件中获取 InputStream(读取 gzipped 本地 xml 文件).

employee.gz

如果有人可以帮助我真的很感激.谢谢

解决方案

此链接适用于 zip.http://techdroid.kbeanie.com/2010/10/unzip-files-in-android.html

我不确定它是否适用于 gz 文件，但您可以尝试一下.开发文档上有关于 GZIPInputStream 类的文档.

http://developer.android.com/reference/java/util/zip/GZIPInputStream.html

这段代码有效.

<上一页>GZIPInputStream inputStream = new GZIPInputStream(new FileInputStream(new File(文件路径")))；String str = IOUtils.convertStreamToString(inputStream);

我使用了一个将输入流转换为字符串的 util 类.您可能希望手动完成阅读部分.

I don't know how to get an InputStream(Read gzipped local xml file) from the locally stored gzip xml file.

employee.gz

If someone Can help I really appreciate. Thanks

解决方案

This link works with zip. http://techdroid.kbeanie.com/2010/10/unzip-files-in-android.html

I am not sure if it will work with gz files, but you could give it a try. There's a documentation on GZIPInputStream class on the dev docs.

http://developer.android.com/reference/java/util/zip/GZIPInputStream.html

This piece of code works.

GZIPInputStream inputStream = new GZIPInputStream(new FileInputStream(new File(
                        "path to file")));

String str = IOUtils.convertStreamToString(inputStream);

I have used a util class which converts the input stream to a string. You might want to do the reading part manually.

这篇关于在 Android 应用程序中读取本地压缩的 XML 文件(gzip)的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！