使用 Child 进行 XML 解析而不是值解析 [英] XML parsing with Child not value parsing

问题描述

使用 Child 解析 XML 而非值解析

XML parsing with Child not value parsing

   import java.io.File;
   import java.io.FileInputStream;

   import javax.xml.xpath.XPath;
   import javax.xml.xpath.XPathConstants;
   import javax.xml.xpath.XPathFactory;

   import org.w3c.dom.Node;
   import org.w3c.dom.NodeList;
   import org.xml.sax.InputSource;

   import com.sun.org.apache.xml.internal.dtm.ref.DTMNodeList;

    public class XPathEvaluator {
    /*
   * ServiceGroup serviceGroup = new ServiceGroup(); List<Service>
    * requiredServices = new ArrayList<Service>(); List<Service>
  * recommandedServices = new ArrayList<Service>(); Service service = new
  * Service();
  */

public void evaluateDocument(File xmlDocument) {

    try {
        XPathFactory factory = XPathFactory.newInstance();
        XPath xPath = factory.newXPath();
        String requiredServicesExpression = "/Envelope/Header";
        InputSource requiredServicesInputSource = new InputSource(
                new FileInputStream(xmlDocument));
        DTMNodeList requiredServicesNodes = (DTMNodeList) xPath.evaluate(
                requiredServicesExpression, requiredServicesInputSource,
                XPathConstants.NODESET);
        System.out.println(requiredServicesNodes.getLength());
        NodeList requiredNodeList = (NodeList) requiredServicesNodes;

        for (int i = 0; i < requiredNodeList.getLength(); i++) {
            Node node = requiredNodeList.item(i);
            System.out.println(node.getChildNodes());

        }

    } catch (Exception e) {
        e.printStackTrace();
    }
}

public static void main(String[] argv) {
    XPathEvaluator evaluator = new XPathEvaluator();
    File xmlDocument = new File("d://eva.xml");
    evaluator.evaluateDocument(xmlDocument);

 }

}

我的 xml 在此我正在尝试解析标头信息

my xml is following in this i am try to parse header information

   <?xml version="1.0" encoding="UTF-8"?>
   <Envelope>
       <Header>
            <User id="MAKRISH"/>
            <Request-Id id="1"/>
            <Type name="Response"/>
            <Application-Source name="vss" version="1.0"/>
            <Application-Destination name="test" />
            <Outgo-Timestamp date="2012-08-24" time="14:50:00"/>
            <DealerCode>08301</DealerCode>
            <Market>00000</Market>
        </Header>
   </Envelope>

我无法获取 Header 子项，如何获取它们在 getchildNodes 方法上给我 null.我已经检查了很多解决方案，但得到了任何东西.

i am not able to get Header child how can i get them it is giving me null on getchildNodes method. i have check for many solution but get any thing.

推荐答案

this related question 有一个使用 xpath 解析 xml 的好例子.

The accepted answer to this related question has a good example of parsing xml using xpath.

我已经调试了你的代码，getChildNodes 调用实际上并没有返回 null，但是它有一个令人困惑的 toString().

I've debugged into your code, and the getChildNodes call is in fact not returning null, but it has got a confusing toString().

这篇关于使用 Child 进行 XML 解析而不是值解析的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！