的JavaScriptSerializer：序列清单+字符串转换成JSON [英] JavaScriptSerializer: Serialize a list + a string into JSON

问题描述

我想使用的JavaScriptSerializer发送一个包，包含一个对象列表，以及一个字符串，确定像ChatLogPath JSON数据。至于我可以告诉大家，那类只能序列化一个对象 - 是名单 - 如果我尝试追加多个的它显然只是创建无效的JSON像{...} {...}这将不的工作。

I want to use JavaScriptSerializer to send a package of JSON data that contains both a list of objects as well as a string, identified like ChatLogPath. As far as I can tell, that class can only serialize one object -- being the list -- and if I try to append multiple ones it obviously just creates invalid JSON like {...}{...} which won't work.

有没有办法做到这一点？我疯狂新的C＃和ASP.NET MVC所以请原谅我，如果这是一个愚蠢的问题：）

Is there any way to do this? I'm insanely new to C# and ASP.NET MVC so forgive me if this is a dumb question :)

编辑：这里是我的code截至目前

here's my code as of right now.

    string chatLogPath = "path_to_a_text_file.txt";
    IEnumerable<ChatMessage> q = ...
    ...
    JavaScriptSerializer json = new JavaScriptSerializer();
    return json.Serialize(q) + json.Serialize(chatLogPath);

将输出的JSON像这样的阵列{...}其次chatLogPath {...}。换句话说，它不能工作，因为这是无效的JSON

Which will output the array like this in JSON { ... } followed by the chatLogPath { ... }. In other words, it can't work since that's invalid JSON.

推荐答案

要获得与阵列和路径一起单一JSON对象最简单的方法是创建一个类或动态对象，每个作为它的属性/字段。

The easiest way to get a single JSON object with the array and path together is to create a class or dynamic object with each as a property/field of it.

类的例子：

public class ChatInformation {
  public IEnumerable<ChatMessage> messages;
  public string chatLogPath;
}
...
var output = new ChatInformation {
  messages = ...,
  chatLogPath = "path_to_a_text_file.txt"
};
return json.Serialize(output);

动态例子（需要.NET 4 +）：

Dynamic example (requires .NET 4+):

dynamic output = new ExpandoObject {
  messages = ...,
  chatLogPath = "path_to_a_text_file.txt"
};
return json.Serialize(output);

匿名类型的例子（如果你不小心有另一个类，也不是你的.NET 4）：

Anonymous Type example (if you don't care to have another class, nor are you on .NET 4):

var output = new {
  messages = ...,
  chatLogPath = "path_to_a_text_file.txt"
};
return json.Serialize(output);

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