AngularJS ui-router:测试 ui-sref [英] AngularJS ui-router: Test ui-sref

问题描述

我正在尝试测试一些视图，它们使用 <a ui-sref='someState'>link</a> 链接到我的应用程序中的其他状态.在我的测试中，我触发了对这些元素的点击，如下所示:

I'm trying to test some views, that are using <a ui-sref='someState'>link</a> to link to other states in my application. In my tests I'm triggering a click on this elements like this:

element.find('a').click()

如果状态切换到someState，我该如何测试?像这样在我的控制器中使用 $state 会很容易:

How do I test, if the state is switched to someState? It would be easy, when using $state in my controller like this:

// in my view
<a ng-click="goTo('someState')">link</a>

// in my controller
$scope.goTo = function(s) {
  $state.go(s)
};

// in my tests
spyOn($state, 'go');
element.find('a').click()
expect($state.go).toHaveBeenCalled()

但是当我使用 ui-sref 时，我不知道要监视什么对象.如何验证我的应用程序处于正确的状态?

But when I use ui-sref I don't know what object to spy on. How can I verify, that my application is in the right state?

推荐答案

我自己找到的.在查看了 Angular ui 路由器源代码后，我在 ui-sref 指令中发现了这一行:

I found it myself. After having a look into the angular ui router source code, I found this line inside the ui-sref directive:

// angular-ui-router.js#2939
element.bind("click", function(e) {
  var button = e.which || e.button;
  if ( !(button > 1 || e.ctrlKey || e.metaKey || e.shiftKey || element.attr('target')) ) {
    // HACK: This is to allow ng-clicks to be processed before the transition is initiated:
    $timeout(function() {
      $state.go(ref.state, params, options);
    });
    e.preventDefault();
  }
});

当元素收到点击时，$state.go 被包装在 $timout 回调中.因此，在您的测试中，您必须注入 $timeout 模块.然后像这样执行 $timeout.flush() :

When the element receives a click, the $state.go is wrapped in a $timout callback. So, in your tests, you have to inject the $timeout module. Then just do a $timeout.flush() like this:

element.find('a').click();
$timeout.flush();
expect($state.is('someState')).toBe(true);

这篇关于AngularJS ui-router:测试 ui-sref的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！