传单在按钮单击时打开特定标记弹出窗口 [英] leaflet open specific marker popup on button click

问题描述

我正在尝试在某些事件(例如，按钮单击)上打开特定标记的弹出窗口.为此，我将 id 属性添加到标记并将所有标记存储在数组中.但是由于某种原因，当我尝试访问数组内的标记的 id 属性时，它是未定义的.

I'm trying to open a specific marker's popup on some event(say, button click). In order to do so I add an id property to a marker and store all markers in an array. But for some reason, the id property of a marker inside of an array is undefined when I try to access it.

var map = L.map('map').setView([51.505, -0.09], 13);
var markers = [];
var marker = L.marker([51.5, -0.09]);
marker["id"]="0";
marker.bindPopup('!');
marker.addTo(map);
markers.push(marker);

openPopupById("0");

function openPopupById(id) {
    for(var marker in markers) {
        alert("Marker's id " + marker["id"] + " target id " + id );
        if (marker["id"] === id) {
            //marker.openPopup();
            alert("opening " + id);
        }
    }
    alert(id);
}

更新好的，我找到了解决方案:我应该将 for 替换为

UPDATE Ok, I found the solution: I should replace for with

for(var i = 0; i < markers.length; ++i)

并以 markers[i]["id"]

但是谁能解释一下为什么第一个版本不起作用?

But can someone explain me why the first version doesn't work?

推荐答案

我认为你的错误是使用push(在markers.push(marker)中)

I think your mistake is the use of push (in markers.push(marker))

要存储标记，您应该使用

To store the markers, you should use

markers["id"] = marker;

你可以这样打开你的弹出窗口

You can open your popup like that

markers["id"].openPopup();

让标记知道他们的 id

For the markers to know their id

marker.id = "id";

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