“Char 不能被取消引用"错误 [英] "Char cannot be dereferenced" error

问题描述

我正在尝试使用char方法isLetter()，它应该返回对应于字符是否为字母的布尔值.但是当我调用该方法时，我收到一条错误消息，指出无法取消引用 char".我不知道取消引用 char 意味着什么或如何修复错误.有问题的陈述是:

I'm trying to use the char method isLetter(), which is supposed to return boolean value corresponding to whether the character is a letter. But when I call the method, I get an error stating that "char cannot be dereferenced." I don't know what it means to dereference a char or how to fix the error. the statement in question is:

if (ch.isLetter()) 
{
....
....
}

有什么帮助吗?取消引用 char 是什么意思?如何避免这样做?

Any help? What does it mean to dereference a char and how do I avoid doing so?

推荐答案

char 类型是原始类型——不是对象——所以它不能被取消引用

The type char is a primitive -- not an object -- so it cannot be dereferenced

取消引用是访问引用所引用的值的过程.由于 char 已经是一个值(不是引用)，它不能被取消引用.

Dereferencing is the process of accessing the value referred to by a reference. Since a char is already a value (not a reference), it can not be dereferenced.

使用Character类:

if(Character.isLetter(c)) {

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