ASP.NET MVC。如何创建一个接受和多/ form-data的操作方法 [英] ASP.NET MVC. How to create Action method that accepts and multipart/form-data

问题描述

我有一个需要接受的multipart / form-data的客户端发送一个POST请求一个控制器方法。该表单数据有2个部分吧。其一是序列化到应用程序/ JSON ，另一部分对象被作为 A照片文件的应用程序/八位字节流 。我有一个方法我的控制器是这样的：

 的[AcceptVerbs（HttpVerbs.Post）
无效的ActionResult照片（PostItem后）
{
}
 

我可以通过 Request.File 没有问题的文件here.However的PostItem为空。
不知道为什么？任何想法

控制器code：

  ///＆LT;总结＆gt;
/// FeedsController
///＆LT; /总结＆gt;
公共类FeedsController：FeedsBaseController
{
    的[AcceptVerbs（HttpVerbs.Post）
    公众的ActionResult照片（FeedItem feedItem）
    {
        //这里feedItem总是空。然而Request.Files [0]给我我需要的文件
        VAR处理器=新ActivityFeedsProcessor（）;
        processor.ProcessFeed（feedItem，Request.Files [0]）;        SetResponse code（System.Net.HttpStatus code.OK）;
        返回新EmptyResult（）;
    }
 

}

在电线上的客户端请求如下：

  {用户代理的东西}
内容类型：多重/ form-data的;边界= 8cdb3c15d07d36a--8cdb3c15d07d36a
内容处置：表格数据; NAME =feedItem
内容类型：文本/ XML{用户ID：1234567的GroupId：123456，PostType：照片，
    PublishTo：店，CreatedTime：2011-03-19 03：22：39Z}--8cdb3c15d07d36a
内容处置：文件;文件名=TESTFILE.TXT
的ContentType：应用程序/八位字节流{字节在这里。除去简洁}
--8cdb3c15d07d36a--
 

解决方案

什么的 FeedItem 类是什么样子？对于我在后信息看它应该是这个样子：

 公共类FeedItem
{
    公众诠释用户ID {搞定;组; }
    公众诠释的GroupId {搞定;组; }
    公共字符串PublishTo {搞定;组; }
    公共字符串PostType {搞定;组; }
    公众的DateTime CreatedTime {搞定;组; }
}
 

，否则它不会被束缚。你可以尝试和更改操作的签名，看看这个作品：

  [HttpPost] //AcceptVerbs(HttpVerbs.Post）是昔日的事
公众的ActionResult照片（INT用户ID，诠释的GroupId，串PublishTo
    串PostType，日期CreatedTime）
{
    //做一些工作在这里
}
 

您可以甚至尝试和 HttpPostedFileBase 参数添加到你的动作：

  [HttpPost]
公众的ActionResult照片（INT用户ID，诠释的GroupId，串PublishTo
    串PostType，日期CreatedTime，HttpPostedFileBase文件）
{
    //最后参数消除了Request.Files需要[0]
    VAR处理器=新ActivityFeedsProcessor（）;
    processor.ProcessFeed（feedItem，文件）;}
 

如果你真的感觉野性和调皮，添加 HttpPostedFileBase 到 FeedItem ：

 公共类FeedItem
{
    公众诠释用户ID {搞定;组; }
    公众诠释的GroupId {搞定;组; }
    公共字符串PublishTo {搞定;组; }
    公共字符串PostType {搞定;组; }
    公众的DateTime CreatedTime {搞定;组; }
    公共HttpPostedFileBase文件{搞定;组; }
}
 

这最后code段可能是你想要什么直到结束，而是一步一步的细分可能会一起帮助你。

这个回答可以帮助你沿着去正确的方向，以及：<一href=\"http://stackoverflow.com/questions/3877448/asp-net-mvc-passing-model-together-with-files-back-to-controller/3878341#3878341\">ASP.NET MVC传递模型* *一起带回到控制器文件

I have a Controller method that needs to accept multipart/form-data sent by the client as a POST request. The form data has 2 parts to it. One is an object serialized to application/json and the other part is a photo file sent as application/octet-stream. I have a method on my controller like this:

[AcceptVerbs(HttpVerbs.Post)]
void ActionResult Photos(PostItem post)
{
}

I can get the file via Request.File without problem here.However the PostItem is null. Not sure why? Any ideas

Controller Code:

/// <summary>
/// FeedsController
/// </summary>
public class FeedsController : FeedsBaseController
{
    [AcceptVerbs(HttpVerbs.Post)]
    public ActionResult Photos(FeedItem feedItem)
    {
        //Here the feedItem is always null. However Request.Files[0] gives me the file I need  
        var processor = new ActivityFeedsProcessor();
        processor.ProcessFeed(feedItem, Request.Files[0]);

        SetResponseCode(System.Net.HttpStatusCode.OK);
        return new EmptyResult();
    }

}

The client request on the wire looks like this:

{User Agent stuff}
Content-Type: multipart/form-data; boundary=8cdb3c15d07d36a

--8cdb3c15d07d36a
Content-Disposition: form-data; name="feedItem"
Content-Type: text/xml

{"UserId":1234567,"GroupId":123456,"PostType":"photos",
    "PublishTo":"store","CreatedTime":"2011-03-19 03:22:39Z"}

--8cdb3c15d07d36a
Content-Disposition: file; filename="testFile.txt"
ContentType: application/octet-stream

{bytes here. Removed for brevity}
--8cdb3c15d07d36a--

解决方案

What does the FeedItem class look like? For what I see in the post info it should look something like:

public class FeedItem
{
    public int UserId { get; set; }
    public int GroupId { get; set; }
    public string PublishTo { get; set; }
    public string PostType { get; set; }
    public DateTime CreatedTime { get; set; }
}

Otherwise it will not be bound. You could try and change the action signature and see if this works:

[HttpPost] //AcceptVerbs(HttpVerbs.Post) is a thing of "the olden days"
public ActionResult Photos(int UserId, int GroupId, string PublishTo
    string PostType, DateTime CreatedTime)
{
    // do some work here
}

You could even try and add a HttpPostedFileBase parameter to your action:

[HttpPost]
public ActionResult Photos(int UserId, int GroupId, string PublishTo
    string PostType, DateTime CreatedTime, HttpPostedFileBase file)
{
    // the last param eliminates the need for Request.Files[0]
    var processor = new ActivityFeedsProcessor();
    processor.ProcessFeed(feedItem, file);

}

And if you're really feeling wild and naughty, add HttpPostedFileBase to FeedItem:

public class FeedItem
{
    public int UserId { get; set; }
    public int GroupId { get; set; }
    public string PublishTo { get; set; }
    public string PostType { get; set; }
    public DateTime CreatedTime { get; set; }
    public HttpPostedFileBase File { get; set; }
}

This last code snippet is probably what you want to end up with, but the step-by-step breakdown might help you along.

This answer might help you along in de right direction as well: ASP.NET MVC passing Model *together* with files back to controller

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