在 R 中处理时间戳 [英] Dealing with timestamps in R
问题描述
我有多个测量值列表.在每个列表中,时间戳都被格式化为一个字符串(2009-12-24 21:00:07.0"),我知道列表中的每个测量都间隔 5 秒.我想在 R 中将所有数据组合成一个巨大的 data.frame.之后我希望能够轻松访问两次测量的时间差,所以我可能应该将数据转换为不同于字符的东西.
I have multiple lists of measurements. In each list have the timestramp formated as a string ("2009-12-24 21:00:07.0") and I know that each measurement in the list is separated by 5 seconds. I want to combine all data into a huge data.frame in R. Afterwards I want to be able to easily access the time difference of two measurements so I probably should convert data into something different than characters.
我应该使用哪种格式来存储时间?我应该使用某些包中的某些时间格式吗?
Which format should I use to store the times? Is there some time format in some package that I should use?
推荐答案
您想要来自基本 R 的(标准)POSIXt
类型,它可以以紧凑形式"作为 POSIXct
(本质上是一个 double 表示自纪元以来的小数秒)或 POSIXlt
中的长格式(包含子元素).很酷的事情是在此定义了算术等 - 请参阅 help(DateTimeClasses)
You want the (standard) POSIXt
type from base R that can be had in 'compact form' as a POSIXct
(which is essentially a double representing fractional seconds since the epoch) or as long form in POSIXlt
(which contains sub-elements). The cool thing is that arithmetic etc are defined on this -- see help(DateTimeClasses)
快速示例:
R> now <- Sys.time()
R> now
[1] "2009-12-25 18:39:11 CST"
R> as.numeric(now)
[1] 1.262e+09
R> now + 10 # adds 10 seconds
[1] "2009-12-25 18:39:21 CST"
R> as.POSIXlt(now)
[1] "2009-12-25 18:39:11 CST"
R> str(as.POSIXlt(now))
POSIXlt[1:9], format: "2009-12-25 18:39:11"
R> unclass(as.POSIXlt(now))
$sec
[1] 11.79
$min
[1] 39
$hour
[1] 18
$mday
[1] 25
$mon
[1] 11
$year
[1] 109
$wday
[1] 5
$yday
[1] 358
$isdst
[1] 0
attr(,"tzone")
[1] "America/Chicago" "CST" "CDT"
R>
至于读入,见help(strptime)
至于区别,也很简单:
R> Jan1 <- strptime("2009-01-01 00:00:00", "%Y-%m-%d %H:%M:%S")
R> difftime(now, Jan1, unit="week")
Time difference of 51.25 weeks
R>
最后,zoo 包 是一个用途广泛且文档齐全的容器用于具有相关日期/时间索引的矩阵.
Lastly, the zoo package is an extremely versatile and well-documented container for matrix with associated date/time indices.
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