从控制器RedirectToAction下载文件（） [英] Download file from controller RedirectToAction()

问题描述

我有我的东西比较简单挣扎的老MVC 1.0应用程序。

I have an old MVC 1.0 application that I am struggling with something relatively simple.

1. 我有一个观点，即允许用户上传文件。


2. 某些服务器端处理不胜枚举。


3. 最后，生成并自动下载到客户端的机器的新文件。

我有步骤1和2的工作。我不能得到的最后一步工作。这里是我的控制器：

I have steps 1 and 2 working. I can not get the final step to work. Here is my controller:

[AcceptVerbs(HttpVerbs.Post)]
public ViewResult SomeImporter(HttpPostedFileBase attachment, FormCollection formCollection, string submitButton, string fileName
{
    if (submitButton.Equals("Import"))
    {
        byte[] fileBytes = ImportData(fileName, new CompanyExcelColumnData());
        if (fileBytes != null)
        {
            RedirectToAction("DownloadFile", "ControllerName", new { fileBytes = fileBytes});
        }
        return View();
    }
    throw new ArgumentException("Value not valid", "submitButton");
}

public FileContentResult DownloadFile(byte[] fileBytes)
{
    return File(
                fileBytes,
                "application/ms-excel",
                string.Format("Filexyz {0}", DateTime.Now.ToString("yyyyMMdd HHmm")));
}

在code执行：

The code executes:

RedirectToAction("DownloadFile", "ControllerName", new { fileBytes = fileBytes});

但文件不会下载。建议表示欢迎和感谢提前。

but the file does not download. Suggestions welcome and thanks in advance.

推荐答案

尝试返回的 的ActionResult ，因为它是最抽象类的动作输出。的ViewResult将迫使你返回查看或PartialView，因此，返回一个文件将获得有关隐式类型converttion异常。

Try to return ActionResult, because it is the most abstract class of the output of actions. ViewResult will force you to return a View or PartialView, so, return a File will get an exception about implicitly converttion type.

[HttpPost]
public ActionResult SomeImporter(HttpPostedFileBase attachment, FormCollection formCollection, string submitButton, string fileName
{
    if (submitButton.Equals("Import"))
    {
        byte[] fileBytes = ImportData(fileName, new CompanyExcelColumnData());
        if (fileBytes != null)
        {
            return File(
                fileBytes,
                "application/ms-excel",
                string.Format("Filexyz {0}", DateTime.Now.ToString("yyyyMMdd HHmm")));
        }
        return View();
    }
    throw new ArgumentException("Value not valid", "submitButton");
}

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