从 data.table 中删除仅包含 NA 的行 [英] Remove lines with only NAs from data.table

问题描述

我想从 data.table 中删除仅包含 NA 的行.

I want to remove the lines from a data.table that only contain NAs.

> tab = data.table(A = c(1, NA, 3), B = c(NA, NA, 3))
> tab
    A  B
1:  1 NA
2: NA NA
3:  3  3

通常我会用 apply(dat, 1, ...) 来做，不幸的是它不适用于 data.table 但它导致我这个不优雅的解决方案:

Normally I would do it with apply(dat, 1, ...) which unfortunately does not work on a data.table but it leads me to this inelegant solution:

> tab[apply(as.data.frame(tab), 1, function(x) !all(is.na(x))), ]
   A  B
1: 1 NA
2: 3  3

如何在不知道列名的情况下以最快的方式实现这一点?

How can this be achieved the fastest way without knowing the column names?

推荐答案

我们可以使用 Reduce 和 is.na 和 &

We can use Reduce with is.na and &

tab[!Reduce(`&`, lapply(tab, is.na))]
#   A  B
#1: 1 NA
#2: 3  3

<小时>

或者一个紧凑但不那么有效的方法是

---

Or a compact but not so efficient approach would be

tab[rowSums(!is.na(tab)) != 0L]

此外，正如 @Frank 所评论的，一种基于联接的方法，

Also, as commented by @Frank, a join based approach,

tab[!tab[NA_integer_], on = names(tab)]

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