在 Fortran 90 中将字符串转换为整数 [英] Converting a string to an integer in Fortran 90

问题描述

我知道 IACHAR(s) 在字符串 s 的第一个字符位置返回 ASCII 字符的代码，但我需要将整个字符串转换为整数.我还有一些字符串(大约 30 个字符串，每个最多包含 20 个字符).有没有办法将它们中的每一个转换为 Fortran 90 中的唯一整数?

I know that IACHAR(s) returns the code for the ASCII character in the first character position of the string s, but I need to convert the entire string to an integer. I also have a few number of strings (around 30 strings, each consists of at most 20 characters). Is there any way to convert each one of them to a unique integer in Fortran 90?

推荐答案

你可以读一个字符串到一个整型变量中:

You can read a string into an integer variable:

module str2int_mod
contains 

  elemental subroutine str2int(str,int,stat)
    implicit none
    ! Arguments
    character(len=*),intent(in) :: str
    integer,intent(out)         :: int
    integer,intent(out)         :: stat

    read(str,*,iostat=stat)  int
  end subroutine str2int

end module

program test
  use str2int_mod
  character(len=20) :: str(3)
  integer           :: int(3), stat(3)

  str(1) = '123' ! Valid integer
  str(2) = '-1'  ! Also valid
  str(3) = 'one' ! invalid

  call str2int(str,int,stat)

  do i=1,3
    if ( stat(i) == 0 ) then
      print *,i,int(i)
    else
      print *,'Conversion of string ',i,' failed!'
    endif
  enddo
end program

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