Ruby 在与源相同的目录中加载配置(yaml)文件 [英] Ruby loading config (yaml) file in same dir as source
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问题描述
在 HOME/path_test/我有:
in HOME/path_test/ I have:
load_test.rb:
load_test.rb:
require 'yaml'
cnf = YAML::load(File.open('config.yml'))
puts cnf['Hello']
config.yml:
config.yml:
Hello: world!!!
当在 HOME/path_test/时,我得到了预期:
when in HOME/path_test/ I get as expected:
-bash-3.2$ ruby load_test.rb
world!!!
当在 HOME/(cd ..) 我得到
when in HOME/ (cd ..) I get
-bash-3.2$ ruby path_test/load_test.rb
path_test/load_test.rb:3:in `initialize': No such file or directory - config.yml (Errno::ENOENT)
from path_test/load_test.rb:3:in `open'
from path_test/load_test.rb:3:in `<main>'
这是正确的行为,但不是我所希望的:)
Which is correct behavior, but not what I had wished for :)
有没有办法加载相对于源文件而不是相对于当前工作目录的 .yml 文件??
Is there a way to load the .yml file relative to the source file, and not relative to the current working DIR??
解决方案(load_Test.rb):
Solution (load_Test.rb):
require 'yaml'
fn = File.dirname(File.expand_path(__FILE__)) + '/config.yml'
cnf = YAML::load(File.open(fn))
puts cnf['Hello']
推荐答案
你应该通过以下方式获取当前文件的路径:
You should get path of the current file by:
cnf = YAML::load_file(File.join(File.dirname(File.expand_path(__FILE__)), 'config.yml'))
从 Ruby 2.0 开始,您可以简化它并使用:
Since Ruby 2.0 you can simplify that and use:
cnf = YAML::load_file(File.join(__dir__, 'config.yml'))
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