引用 YAML(对于 Travis CI) [英] Quoting YAML (for Travis CI)

问题描述

如何在 YAML 中转义整行?我想要 json='{"title": "travis_saulshanabrook_site","key": "'$(cat ~/.ssh/id_rsa.pub)'"}' 在列表中，但我无法将其解析为字符串.我可以在整行周围加上单引号，但是我必须转义字符串中的每个单引号，这使得它很难阅读.该字符串将在 Travis CI

How would I escape a whole line in YAML? I want to have json='{"title": "travis_saulshanabrook_site","key": "'$(cat ~/.ssh/id_rsa.pub)'"}' in a list, but I can't get it to parse into a string. I can put single quotes around the whole line, but then I would have to escape every single quote in my string, making it very hard to read. The string will be run as a bash command in Travis CI

推荐答案

最优雅的解决方案是使用 文字样式 | 指示符，使用 - 修饰符去除最后的换行符.这样就不需要额外的引号.

The most elegant solution is to use the literal style | indicator, with the - modifier to strip the final newline. That way there are no extra quotes necessary.

如果这个标量恰好是 YAML 文件中的唯一内容，请使用:

If this scalar happens to be the only thing in a YAML file use:

|-
  json='{"title": "travis_saulshanabrook_site","key": "'$(cat ~/.ssh/id_rsa.pub)'"}'

如果是键abc的映射值:

abc: |-
  json='{"title": "travis_saulshanabrook_site","key": "'$(cat ~/.ssh/id_rsa.pub)'"}'

或者如果它是列表的一部分:

or if it is part of a list:

- |-
  json='{"title": "travis_saulshanabrook_site","key": "'$(cat ~/.ssh/id_rsa.pub)'"}'

这篇关于引用 YAML(对于 Travis CI)的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！