使用 mockito 模拟使用通配符返回泛型的方法 [英] mocking a method that return generics with wildcard using mockito

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问题描述

我使用的是 mockito 1.9.5.我有以下代码:

公共类 ClassA {公共列表getMyInterfaces() {返回空值;}公共静态无效testMock(){列出<我的界面>接口 = 新的 ArrayList<>();ClassA classAMock = mock(ClassA.class);when(classAMock.getMyInterfaces()).thenReturn(interfaces);}

我得到一个编译错误 thenReturn(interfaces) 说:

"类型中的thenReturn(List)方法OngoingStubbing<List<capture#1-of ?扩展我的接口>>不适用于论点(列表<MyInterface>)"

但是,当我使用 mockito 的 thenAnswer 方法时,我没有收到错误消息.谁能告诉我发生了什么事?为什么我在使用 thenReturn 方法时会收到错误消息?当 ClassA 由第三方提供且无法修改时,是否有其他方法可以解决此问题?

解决方案

编辑:从 Mockito 1.10.x 开始,嵌入在类中的泛型类型现在被 Mockito 用于深度存根.IE.

公共接口 A<T 扩展 Observer &可比

Mockito 尽力获取编译器嵌入的类型信息,但是当应用擦除时,mockito 只能返回 Object 的模拟.

<小时>

原创:嗯,这更多是泛型的问题,而不是 Mockito 的问题.对于泛型,您应该阅读 Angelika Langer 在它们上写的内容.对于当前主题,即通配符,请阅读此部分.p>

但简而言之,您可以使用 Mockito 的其他语法来帮助您解决当前的情况:

doReturn(interfaces).when(classAMock).getMyInterfaces();

或者使用 BDD 别名:

willReturn(interfaces).given(classAMock).getMyInterfaces();

尽管如此,您可以编写更通用友好的包装器.这将有助于未来的开发人员使用相同的第 3 方 API.

<小时>

附带说明:您不应该模拟您不拥有的类型,这可能会导致许多错误和问题.相反,你应该有一些包装.例如 DAO 和存储库就代表了这样的想法,人们将模拟 DAO 或存储库接口,而不是 JDBC/JPA/hibernate 的东西.有很多关于此的博客文章:

I'm using mockito 1.9.5. I have the following code:

public class ClassA  {

public List<? extends MyInterface> getMyInterfaces() {
    return null;
}

public static void testMock() {
    List<MyInterface> interfaces = new ArrayList<>();
    ClassA classAMock = mock(ClassA.class);
    when(classAMock.getMyInterfaces()).thenReturn(interfaces);      
}

I get a compilation error for the thenReturn(interfaces) saying:

"The method thenReturn(List<capture#1-of ? extends MyInterface>) in the type 
 OngoingStubbing<List<capture#1-of ? extends MyInterface>> is not applicable for the arguments 
 (List<MyInterface>)"

However, when I use the thenAnswer method of mockito, I don't get the error. Can anyone tell me what's going on? Why do I get the error when I use the thenReturn method? Is there any other way to solve this problem when ClassA is provided by a 3rd party and cannot be modified?

解决方案

EDIT : Starting from Mockito 1.10.x, generics types that are embedded in the class are now used by Mockito for deep stubs. ie.

public interface A<T extends Observer & Comparable<? super T>>  {
  List<? extends B> bList();
  T observer();
}

B b = deep_stubbed.bList().iterator().next(); // returns a mock of B ; mockito remebers that A returns a List of B
Observer o = deep_stubbed.observer(); // mockito can find that T super type is Observer
Comparable<? super T> c = deep_stubbed.observer(); // or that T implements Comparable

Mockito tries its best to get type information that the compiler embeds, but when erasure applies, mockito cannot do anything but return a mock of Object.


Original : Well that's more of an issue with generics than with Mockito. For generics, you should read what Angelika Langer wrote on them. And for the current topic, i.e. wildcards, read this section.

But for short, what you could use is the other syntax of Mockito to help with your current situation :

doReturn(interfaces).when(classAMock).getMyInterfaces();

Or with the BDD aliases :

willReturn(interfaces).given(classAMock).getMyInterfaces();

Nevertheless, you could write wrappers that are more generic friendly. That will help future developers working with same 3rd party API.


As a side note: you shouldn't mocks type you don't own, it can lead to many errors and issues. Instead you should have some wrapper. DAO and repositories for example represent such idea, one will mock the DAO or repository interface, but not the JDBC / JPA / hibernate stuff. There are many blog posts about that:

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