解码 Google Maps 嵌入参数 [英] Decoding the Google Maps embedded parameters
问题描述
我希望能够提取嵌入网站的谷歌地图的位置(在 本网站).
I would like to be able to extract the location of Google Maps embedded in a website (random example found at the bottom of this website).
<iframe src="https://www.google.com/maps/embed?pb=!1m18!1m12!1m3!1d3128.340699934565!2d-0.46482818466529047!3d38.3642391796565!2m3!1f0!2f0!3f0!3m2!1i1024!2i768!4f13.1!3m3!1m2!1s0xd62377123a70817%3A0x85e89b65fcf7c648!2sCalle+Cruz+de+Piedra%2C+4%2C+03015+Alicante!5e0!3m2!1ses!2ses!4v1476192292052" width="100%" height="350" frameborder="0" style="border:0" allowfullscreen=""></iframe>所以，基本上我想从地图 URL 中提取精确位置:
So, basically I want to extract the pinpoint location from the Maps URL:
https://www.google.com/maps/embed?pb=!1m18!1m12!1m3!1d3128.340699934565!2d-0.46482818466529047!3d38.3642391796565!2m3!1f0!2f0!3f0!3m2!1i1024!2i768!4f13.1!3m3!1m2!1s0xd62377123a70817%3A0x85e89b65fcf7c648!2sCalle+Cruz+de+Piedra%2C+4%2C+03015+Alicante!5e0!3m2!1ses!2ses!4v1476192292052
网址设计
Google 似乎在这里使用了专有的参数设计.此博客条目和这篇 Stackoverflow 帖子 很好地总结了如何理解这些参数.参数的结构类似于 (![id][type][value])，类型:
The URL design
Google seems to use a proprietary parameter design here. This blog entry and this Stackoverflow post did a good job summarizing how these parameters can be understood. The parameters are structured like (![id][type][value]), with types:
m: matrix
f: float
d: double
i: integer
b: boolean
e: enum (as integer)
s: string
u: unsigned int
矩阵可以封装多个数据条目，例如.G.!1m3!1i2!1i4!1i17 表示ID为1的矩阵包含三个整数值[2, 4, 17].
Matrices can encapsulate multiple data entries, e. g. !1m3!1i2!1i4!1i17 means that the matrix with the ID 1 contains the three integer values [2, 4, 17].
有了这些知识，参数可以这样构造:
With this knowledge, the parameters can be structured like this:
!1m18
!1m12
!1m3
!1d3128.340699934565
!2d-0.46482818466529047
!3d38.3642391796565
!2m3
!1f0
!2f0
!3f0
!3m2
!1i1024
!2i768
!4f13.1
!3m3
!1m2
!1s0xd62377123a70817:0x85e89b65fcf7c648
!2sCalle Cruz de Piedra, 4, 03015 Alicante
!5e0
!3m2
!1ses
!2ses
!4v1476192292052
现在看起来很简单，我们几乎可以以明文形式看到坐标.但是作为博客条目指出，参数
Now it seems to be easy, we see coordinates almost in clear-text. But as the blog entry points out, the parameters
!1d3128.340699934565
!2d-0.46482818466529047
!3d38.3642391796565
是不是精确定位的位置，而是显示地图的中心.它们很相似，但有时非常不同.更改坐标和/或地址不会导致出现不同的地图.
are not the position of the pinpoint, but the center of the shown map. They are similar, but at times very different. Changing the coordinates and/or the address will not result in a different map.
仅当更改参数!1s0xd62377123a70817:0x85e89b65fcf7c648时，地图显示会中断，这意味着该参数会解码精确定位的位置.
Only when changing the parameter !1s0xd62377123a70817:0x85e89b65fcf7c648, the map display will break, meaning this parameter decodes the location of the pinpoint.
只是，用什么编码?
在博客条目(从 2016 年 8 月开始)，地图链接的构建方式不同.还有一个参数是base64编码的经纬度坐标:
In the blog entry (from August 2016), the Maps link is built up differently. There is another parameter which encodes the longitude and latitude coordinates in base64:
zMzfCsDQ3JzM0LjUiUyAxNDXCsDAwJzU2LjYiRQ ----base64---> 37°47'34.5"S 145°00'56.6"E
以类似的方式，这个新参数的坐标应该有望解码:
In a similar manner, the coordinates of this new parameter should hopefully decode:
0xd62377123a70817:0x85e89b65fcf7c648 ----????----> 38.364236,-0.462649
它看起来像十六进制编码，但是在转换为整数时(964394229279688727:9649133063979386440)，这与我所知道的系统中的地理坐标不对应.
It looks like hexadecimal encoding, but when converting to integer (964394229279688727:9649133063979386440), this does not correspond to geographic coordinates in a system I know.
那么，谁能破解密码?任何帮助表示赞赏.
So, who can crack the code? Any help appreciated.
推荐答案
这个中间不是最终的答案，后续有))，只是一些想法
This intermediate is not the final answer, and the sequel follows)), just some thoughts
未记录的方法.(使用 ftid 而不是 place_id 参数)
Places API 网络服务
未来不保修:
Undocumented method. (with ftid instead of place_id parameter)
Places API Web Service
No warranty in future:
https://maps.googleapis.com/maps/api/place/details/json?key=YOUR_API_KEY&ftid=0xd62377123a70817:0x85e89b65fcf7c648&
记录的请求是:
https://maps.googleapis.com/maps/api/place/details/json?key=YOUR_API_KEY&placeid=ChIJFwinI3E3Yg0RSMb3_GWb6IU
此请求需要 API 密钥设置 API 密钥
Need API KEY for this requests Setting up API keys
来自 Google 的回答:(JSON - 轻量级解析)
Answer from Google: (JSON - light parsing)
{
"html_attributions" : [],
"result" : {
"address_components" : [
{
"long_name" : "4",
"short_name" : "4",
"types" : [ "street_number" ]
},
{
"long_name" : "Calle Cruz de Piedra",
"short_name" : "Calle Cruz de Piedra",
"types" : [ "route" ]
},
{
"long_name" : "Alacant",
"short_name" : "Alacant",
"types" : [ "locality", "political" ]
},
{
"long_name" : "Alicante",
"short_name" : "A",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "Comunidad Valenciana",
"short_name" : "Comunidad Valenciana",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "Spain",
"short_name" : "ES",
"types" : [ "country", "political" ]
},
{
"long_name" : "03015",
"short_name" : "03015",
"types" : [ "postal_code" ]
}
],
"adr_address" : "u003cspan class="street-address"u003eCalle Cruz de Piedra, 4u003c/spanu003e, u003cspan class="postal-code"u003e03015u003c/spanu003e u003cspan class="locality"u003eAlacantu003c/spanu003e, u003cspan class="region"u003eAlicanteu003c/spanu003e, u003cspan class="country-name"u003eSpainu003c/spanu003e",
"formatted_address" : "Calle Cruz de Piedra, 4, 03015 Alacant, Alicante, Spain",
"geometry" : {
"location" : {
"lat" : 38.3642358,
"lng" : -0.4626489
},
"viewport" : {
"northeast" : {
"lat" : 38.3655847802915,
"lng" : -0.4612999197084979
},
"southwest" : {
"lat" : 38.3628868197085,
"lng" : -0.463997880291502
}
}
},
"icon" : "https://maps.gstatic.com/mapfiles/place_api/icons/geocode-71.png",
"id" : "ce1aa5a252b86d559268866a6a4858db9bba3dff",
"name" : "Calle Cruz de Piedra, 4",
"place_id" : "ChIJFwinI3E3Yg0RSMb3_GWb6IU",
"reference" : "CmRbAAAAn6NLYXEs-ttLvUlgjnh5aDHt-LR_hXe6JmUN8fzv6MJ7Q50xt_zUU_WlTc3aL_BQc70-1YjEb6Soluro5rA8cIFJG_w08RSr_JWo_SFEFc1Ncme_dKVKsPX6Q0LtO8gWEhACTzabAMLQfM5xt1_BNsywGhSZr0WRGlutqeuRgs-IY41ndk3yoQ",
"scope" : "GOOGLE",
"types" : [ "street_address" ],
"url" : "https://maps.google.com/?q=Calle+Cruz+de+Piedra,+4,+03015+Alacant,+Alicante,+Spain&ftid=0xd62377123a70817:0x85e89b65fcf7c648",
"utc_offset" : 60,
"vicinity" : "Alacant"
},
"status" : "OK"
}
设置 API 密钥
如果您的客户端应用程序不使用 OAuth 2.0，那么它在调用在 Google Cloud Platform 项目中启用的 API 时必须包含 API 密钥.应用程序将此密钥作为 key=API_key 参数传递给所有 API 请求.创建应用程序的 API 密钥:
If your client application does not use OAuth 2.0, then it must include an API key when it calls an API that's enabled within a Google Cloud Platform project. The application passes this key into all API requests as a key=API_key parameter. To create your application's API key:
- 转到 API 控制台.
- 从项目列表中选择一个项目或创建一个新项目.
- 如果 API 和服务页面尚未打开，打开左侧菜单并选择 APIs &服务.
- 在左侧，选择凭据.
- 点击创建凭据，然后选择API密钥.
- Go to the API Console.
- From the projects list, select a project or create a new one.
- If the APIs & services page isn't already open, open the left side menu and select APIs & services.
- On the left, choose Credentials.
- Click Create credentials and then select API key.
注意:除了阅读此页面上的说明外，请务必阅读 安全使用 API 密钥的最佳实践.
Note: In addition to reading the instructions on this page, be sure to read Best practices for securely using API keys.
(草稿)未删除历史记录
仅供测试！临时解决方案:
for test only! temporary solution:
curl "https://www.google.com/maps/place/data=!4m2!3m1!1s0xd62377123a70817:0x85e89b65fcf7c648" -s -b -L -H "user-agent: Googlebot/2.1 (+http://www.google.com/bot.html)" | FIND """0xd62377123a70817:0x85e89b65fcf7c648"","
在命令提示符下回答:,["0xd62377123a70817:0x85e89b65fcf7c648",null,null,[null,null,38.364235799999996,-0.4626489]
Answer in command prompt: ,["0xd62377123a70817:0x85e89b65fcf7c648",null,null,[null,null,38.364235799999996,-0.4626489]
CURL 那里如果需要
搜索继续......
我认为，这个 (0xd62377123a70817:0x85e89b65fcf7c648) 是 GoogleMap 数据库中地图对象的 ID.点击 URL1 时.
I think, this (0xd62377123a70817:0x85e89b65fcf7c648) is ID of map object in GoogleMap database. When click URL1.
如果你想要地理坐标，请点击 URL2，如果需要创建链接作为 EMBED 没有问题，结果如下:
if you want geographic coordinates then click URL2 please and next if need create link as EMBED no problem, result below:
src="https://www.google.com/maps/embed?pb=
!1m18
!1m12
!1m3
!1d782.0856626047412
!2d-0.46311117079625247
!3d38.36419405026406
!2m3
!1f0
!2f0
!3f0
!3m2
!1i1024
!2i768
!4f13.1
!3m3
!1m2
!1s0x0%3A0x0
!2zMzjCsDIxJzUxLjEiTiAwwrAyNyc0NS4yIlc
!5e0
!3m2
!1ses
!2ses
!4v1509474812934"
它是 FTID (0xd62377123a70817:0x85e89b65fcf7c648)
ftid 参数是某些地图对象的唯一标识符，就像 fid 和 cid 一样.
需要在地图上但不属于本地数据库的位置由 ftid 参数标识.无法通过 Places 声明这些类型的 Maps 对象.
it is FTID (0xd62377123a70817:0x85e89b65fcf7c648)
The ftid parameter is a unique identifier for certain map objects, just as fid and cid are.
Locations that need to be on the map but are not part of the Local database are identified by the ftid parameter. It is not possible to claim these type of Maps objects through Places.
API Google Places 和其他人使用 place-id
API Google Places and others work with place-id
for (Calle Cruz de Piedra, 4 03015 Alicante) place-id = ChIJFwinI3E3Yg0RSMb3_GWb6IU
for (Calle Cruz de Piedra, 4 03015 Alicante) place-id = ChIJFwinI3E3Yg0RSMb3_GWb6IU
(地点 -> 地点 ID)
https://developers.google.com/maps/documentation/javascript/examples/places-placeid-finder
和反向(place-id->place)
https://developers.google.com/maps/documentation/javascript/examples/geocoding-place-id
(place -> place-id)
https://developers.google.com/maps/documentation/javascript/examples/places-placeid-finder
and Reverse (place-id->place)
https://developers.google.com/maps/documentation/javascript/examples/geocoding-place-id
现在:
place-id 到 location - 好的
https://developers.google.com/maps/documentation/地理编码/intro?hl=en#ReverseGeocoding
FTID 到 location -?问题开放......快速和自动
FTID to location -? question open... for fast and automatic
超越谷歌:
https://google.com/maps?ftid=0xd62377123a70817:0x85e89b65fcf7c648
https://www.google.com/maps/place/Calle+Cruz+de+Piedra,+4,+03015+Alicante,+%D0%98%D1%81%D0%BF%D0%B0%D0%BD%D0%B8%D1%8F/@38.3642358,-0.4648376,17z/data=!3m1!4b1!4m5!3m4!1s0xd62377123a70817:0x85e89b65fcf7c648!8m2!3d38.3642358!4d-0.4626489
也适用于大西洋:
https://google.com/maps?ftid=0xadd28c30ec90d79%3A0x44652457c0696504
关于 Google Maps Embed API 的两个词:
and two words about Google Maps Embed API:
<iframe
src="https://www.google.com/maps/embed?pb=
!1m3
!3m2
!1m1
!1s0xd62377123a70817%3A0x85e89b65fcf7c648"
width="400" height="400" frameborder="0" style="border:0" allowfullscreen>
</iframe>m 使用以下语法创建块:1 数字 - ID 或当前块中的位置?2 数字 - 值 = 新块的大小
m create Block with this syntax:
1 Digital - ID or place in current block?
2 Digital - value = size of new block
!<ID>m<value>
!1m3
!3m2
!1m1
!1s0xd62377123a70817%3A0x85e89b65fcf7c648
{}
{,,{}}
{,,{{}}}
{,,{{1s}}}
!1:{}
!1:{!3:{}}
!1:{!3:{!1:{}}}
!1:{!3:{!1:{1s}}}
我希望这会有所帮助！
这篇关于解码 Google Maps 嵌入参数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
