解析用户名以提取用户位置 Twitter [英] Parse User name for extracting user location Twitter

查看:36
本文介绍了解析用户名以提取用户位置 Twitter的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试从 twitter 中获取与用户名相关的用户位置.

I am trying to scrape user location with respect to user names from twitter.

输入:用户列表有超过50K个用户名

Input: The user list has more than 50K User names

AkkiPritam,6.77E+17,12/15/2015,#chennaifloods
AkkiPritam,6.77E+17,12/15/2015,#bhoomikatrust
AkkiPritam,6.77E+17,12/15/2015,#akshaykumar
gischethans,6.77E+17,12/15/2015,#chennaifloods
mid_day,6.77E+17,12/15/2015,#bollywood
mid_day,6.77E+17,12/15/2015,#chennaifloods
Nanthivarman16,6.77E+17,12/15/2015,#admkfails
Nanthivarman16,6.77E+17,12/15/2015,#jayafails
Nanthivarman16,6.77E+17,12/15/2015,#stickergovt
Nanthivarman16,6.77E+17,12/15/2015,#chennaifloods
AdilaMatra,6.77E+17,12/15/2015,#chennaifloods
AdilaMatra,6.77E+17,12/15/2015,#climatechange
AdilaMatra,6.77E+17,12/15/2015,#delhichokes
AdilaMatra,6.77E+17,12/15/2015,#smog
HDFCERGOGIC,6.77E+17,12/15/2015,#chennaifloods
HDFCERGOGIC,6.77E+17,12/15/2015,#tnfloods
ImSoorej,6.77E+17,12/15/2015,#chennaifloods
ImSoorej,6.77E+17,12/15/2015,#chennaimicr

代码:我想查找地理位置,可能是地理坐标.

Code: I want to find geo location possibly geo coordinates.

from __future__ import print_function
import tweepy
from tweepy import OAuthHandler
from tweepy import Stream
from tweepy.streaming import StreamListener
import pandas as pd
import csv

consumer_key = 'xyz'
consumer_secret = 'xyz'
access_token = 'xyz'
access_token_secret = 'xyz'

data = pd.read_csv('user_keyword.csv')
df = ['user_name', 'user_id', 'date', 'keyword']

def get_user_details(username):
        userobj = api.get_user(username)
        return userobj

if __name__ == '__main__':
    #authenticating the app (https://apps.twitter.com/)
    auth = tweepy.auth.OAuthHandler(consumer_key, consumer_secret)
    auth.set_access_token(access_token, access_token_secret)
    api = tweepy.API(auth)

    username = df['user_name']
    userOBJ = get_user_details(username)
    print(userOBJ.location)

错误:无法将用户名解析为程序.

Error: Trouble parsing the usernames into program.

Traceback (most recent call last):
  File "user_profile_location.py", line 38, in <module>
    username = df['user_name']
TypeError: list indices must be integers, not str

推荐答案

你正在使用'data'来定义你的DataFrame和'df'我认为应该是DataFrame的列

You are using 'data' to define your DataFrame and 'df' for what I think should be the columns of the DataFrame

data = pd.read_csv('user_keyword.csv')
df = ['user_name', 'user_id', 'date', 'keyword']

我假设 user_keyword.csv 文件没有标题,尝试添加:

I assume that the user_keyword.csv file has no header, try adding:

data.columns = df

它会将列名更改为存储在 df 中的值.然后稍后代替:

It will change the column names to the values stored in df. Then later instead of:

username = df['user_name']

试试:

username = data['user_name']

请记住,现在用户名是一整列,因此 get_user_details(username) 不应期待单个字符串.

Keep in mind that now username is a whole column so get_user_details(username) should not be expecting a single string.

这篇关于解析用户名以提取用户位置 Twitter的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆