前 2 个最大值，不包括重复值 [英] Top 2 max value excluding duplicate values

问题描述

示例数据:

Name       | Domain    | Count | datetime
----------------------------------------------------
John       | google    | 5     | 2019-07-09 01:00:01
John       | apple     | 6     | 2019-07-09 01:02:01
John       | apple     | 8     | 2019-07-09 01:03:01
John       | google    | 10    | 2019-07-09 01:11:01
John       | dos       | 1     | 2019-07-09 01:11:01
John       | dos       | 3     | 2019-07-09 01:11:01

预期输出:

Name       | max_Domain1| max_Count1 | max_Domain2 | max_Count2 | datetime
--------------------------------------------------------------------------
John       | google     | 10          | apple      | 8         |   2019-07-09

我尝试在分区上使用 row_number()，但它给我的日期值与前 2 个最大值相同.

I tried using row_number() over the partition, but it is giving me the same date values as top 2 maximum.

select t.*,
             row_number() over (partition by name, date(datetime) order by count desc) as seqnum
      from table t
      where datetime >= '2019-07-08' and
            datetime < '2019-07-09'

推荐答案

试试以下:

select name, domain, count,  CONVERT(varchar(10),datetime, 126) as datetime
from
(
select top 2 t.*
from tab t
where datetime >= CONVERT(datetime,'2019-07-08', 101) and
      datetime < CONVERT(datetime,'2019-07-10', 101)
order by row_number() over (partition by name, domain, cast(datetime as date) order by count desc) asc, count desc
) as t2
order by t2.datetime asc

示例这里

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